1
MHT CET 2021 22th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A nucleus breaks into two nuclear parts, which have their velocity ratio $$2: 1$$. The ratio of their nuclear radii will be

A
$$\sqrt{2}$$
B
$$\frac{1}{2}$$
C
$$\frac{1}{2^{1 / 3}}$$
D
$$\frac{1}{\sqrt{2}}$$
2
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Ratio centripetal acceleration for an electron revolving in 3rd and 5th Bohr orbit of hydrogen atom is

A
425 : 18
B
625 : 81
C
125 : 27
D
221 : 36
3
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

When an electron in hydrogen atom jumps from third excited state to the ground state, the de-Broglie wavelength associated with the electron becomes

A
$$\left(\frac{1}{2}\right)^{\text {th }}$$
B
$$\left(\frac{1}{4}\right)^{\text {th }}$$
C
$$\left(\frac{1}{8}\right)^{\text {th }}$$
D
$$\left(\frac{1}{6}\right)^{\text {th }}$$
4
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

'$$\lambda_1$$' is the wavelength of series limit of Lyman series, '$$\lambda_2$$' is the wavelength of the first line line of Lyman series and '$$\lambda_3$$' is the series limit of the Balmer series. Then the relation between $$\lambda_1, \lambda_2$$ and $$\lambda_3$$ is

A
$$\frac{1}{\lambda_1}-\frac{1}{\lambda_2}=\frac{1}{\lambda_3}$$
B
$$\frac{1}{\lambda_1}=\frac{1}{\lambda_2}-\frac{1}{\lambda_3}$$
C
$$\lambda_2=\lambda_1+\lambda_3$$
D
$$\lambda_1=\lambda_2+\lambda_3$$
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