MHT CET 2025 22nd April Morning Shift | Atoms and Nuclei Question 4 | Physics

${ }_{88} \mathrm{R}_{\mathrm{a}}^{226}$ is converted into ${ }_{82} \mathrm{P}_{\mathrm{b}}^{206}$ by emission of alpha ( $\alpha$ ) and beta ( $\beta$ ) particles. The number of alpha and beta particles emitted are respectively

5, 4

4, 5

6, 4

4, 6

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

Out of the following transitions in hydrogen atom, identify the transition which emits photons of highest frequency.

$\mathrm{n}=1$ to $\mathrm{n}=2$

$\mathrm{n}=2$ to $\mathrm{n}=1$

$n=2$ to $n=6$

$n=6$ to $n=2$

MHT CET 2025 21st April Evening Shift

MCQ (Single Correct Answer)

-0

Using Bohr's quantization condition, the rotational kinetic energy in the third orbit for a diatomic molecule is ( $h=$ Planck's constant, $\mathrm{I}=$ moment of inertia of diatomic molecule)

$\frac{9 h^2}{8 \pi^2 I}$

$\frac{3 \mathrm{~h}^2}{8 \pi^2 \mathrm{I}}$

$\frac{6 h^2}{8 \pi I}$

$\frac{12 h^2}{7 \pi^2 I}$

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

-0

Which of the following transitions in hydrogen atom emit photons of highest frequency? ( $\mathrm{n}=$ principle quantum number)

$\mathrm{n}=1$ to $\mathrm{n}=3$

$\mathrm{n}=2$ to $\mathrm{n}=4$

$\mathrm{n}=5$ to $\mathrm{n}=3$

$\mathrm{n}=2$ to $\mathrm{n}=1$

PREVIOUS NEXT

MHT CET Subjects