MHT CET 2025 23rd April Evening Shift | Fluid Mechanics Question 2 | Physics

The amount of work done in blowing a soap bubble such that its diameter increases from $\mathrm{d}_1$ to $\mathrm{d}_2$ is ( $\mathrm{T}=$ surface tension of soap solution)

$\quad 4 \pi\left(\mathrm{~d}_2^2-\mathrm{d}_1^2\right) \mathrm{T}$

$\quad 8 \pi\left(\mathrm{~d}_2^2-\mathrm{d}_1^2\right) \mathrm{T}$

$\pi\left(d_2^2-d_1^2\right) \mathrm{T}$

$\quad 2 \pi\left(d_2^2-d_1^2\right) \mathrm{T}$

MHT CET 2025 23rd April Evening Shift

MCQ (Single Correct Answer)

-0

The energy needed for breaking a liquid drop of radius ' $R$ ' into 216 droplets, each of radius ' $r$ ' is ' $x$ ' times $T R^2$. The value of ' $x$ ' is [ $T=$ surface tension of the liquid].

$4 \pi$

$12 \pi$

$180 \pi$

$20 \pi$

MHT CET 2025 23rd April Morning Shift

MCQ (Single Correct Answer)

-0

The excess pressure inside first soap bubble is three times that of a second soap bubble. The ratio of volumes of the first to second bubble

$1: 3$

$1: 9$

$1: 27$

$27: 1$

MHT CET 2025 23rd April Morning Shift

MCQ (Single Correct Answer)

-0

A disc of paper of radius ' $R$ ' has a hole of radius ' $r$ '. It is floating on a liquid of surface tension ' T '. The force of surface tension on the disc is

$2 \pi \mathrm{~T}(\mathrm{R}-\mathrm{r})$

$2 \pi \mathrm{~T}(\mathrm{R}+\mathrm{r})$

$3 \pi \mathrm{TR}$

$4 \pi \mathrm{~T}(\mathrm{R}+\mathrm{r})$

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