MHT CET 2024 16th May Evening Shift | Probability Question 48 | Mathematics

Numbers are selected at random, one at a time from two digit numbers $10,11,12 \ldots ., 99$ with replacement. An event $E$ occurs if and only if the product of the two digits of a selected number is 18 . If four numbers are selected, then probability that the event E occurs at least 3 times is

$\frac{87}{90^4}$

$\frac{348}{90^4}$

$87\left(\frac{4}{90}\right)^4$

$\left(\frac{4}{10}\right)^4$

MHT CET 2024 16th May Evening Shift

MCQ (Single Correct Answer)

-0

Two friends A and B apply for a job in the same company. The probabilities of A getting selected is $\frac{2}{5}$ and that of B is $\frac{4}{7}$. Then the probability, that one of them is selected, is

$\frac{8}{35}$

$\frac{18}{35}$

$\frac{26}{35}$

$\frac{34}{35}$

MHT CET 2024 16th May Morning Shift

MCQ (Single Correct Answer)

-0

If a random variable X has the following probability distribution values

$\mathrm{X}$	0	1	2	3	4	5	6	7
$\mathrm{P(X):}$	0	$\mathrm{k}$	$\mathrm{2k}$	$\mathrm{2k}$	$\mathrm{3k}$	$\mathrm{k^2}$	$\mathrm{2k^2}$	$\mathrm{7k^2+k}$

Then $P(X \geq 6)$ has the value

$\frac{19}{100}$

$\frac{81}{100}$

$\frac{9}{100}$

$\frac{91}{100}$

MHT CET 2024 16th May Morning Shift

MCQ (Single Correct Answer)

-0

A random variable X takes the values $0,1,2,3$ and its mean is 1.3 . If $\mathrm{P}(\mathrm{X}=3)=2 \mathrm{P}(\mathrm{X}=1)$ and $P(X=2)=0.3$, then $P(X=0)$ is

0.2

0.1

0.3

0.4

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