MHT CET 2021 20th September Morning Shift | Fluid Mechanics Question 54 | Physics

Let '$$\mathrm{R_1}$$' and '$$\mathrm{R_2}$$' are radii of two mercury drops. A big mercury drop is formed from them under isothermal conditions. The radius of the resultant drop is

$$\sqrt{\mathrm{R}_1^2+\mathrm{R}_2^2}$$

$$\left(\mathrm{R}_1^3+\mathrm{R}_2^3\right)^{\frac{1}{3}}$$

$$\sqrt{\mathrm{R}_1^2-\mathrm{R}_2^2}$$

$$\frac{\mathrm{R}_1+\mathrm{R}_2}{2}$$

MHT CET 2021 20th September Morning Shift

MCQ (Single Correct Answer)

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The force required to take away a flat circular plate of radius $$2 \mathrm{~cm}$$ from the surface of water is $$\left[\right.$$Surface tension of water $$\left.=70 \times 10^{-3} \mathrm{Nm}^{-1}, \pi=\frac{22}{7}\right]$$

$$4.4 \times 10^{-4} \mathrm{~N}$$

$$8.8 \times 10^{-3} \mathrm{~N}$$

$$6.6 \times 10^{-4} \mathrm{~N}$$

$$11 \times 10^{-3} \mathrm{~N}$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

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Water rises in a capillary tube of radius $$r$$ upto a height $$h$$. The mass of water in a capillary is $$m$$. The mass of water that will rise in a capillary of radius $$\frac{r}{4}$$ will be

$$4 m$$

$$\frac{m}{4}$$

$$m$$

$$\frac{4}{m}$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

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A small metal sphere of mass $$M$$ and density $$d_1$$ when dropped in a jar filled with liquid moves with terminal velocity after sometime. The viscous force acting on the sphere is ($$d_2=$$ density of liquid and $$g=$$ gravitational acceleration)

$$M g\left(\frac{d_1}{d_2}\right)$$

$$M g\left(1-\frac{d_2}{d_1}\right)$$

$$M g\left(\frac{d_2}{d_1}\right)$$

$$M g\left(1-\frac{d_1}{d_2}\right)$$

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