MHT CET 2024 2nd May Evening Shift | Moving Charges and Magnetism Question 36 | Physics

The magnetic field at the centre of a current carrying circular coil of area ' $A$ ' is ' $B$ '. The magnetic moment of the coil is ( $\mu_0=$ permeability of free space)

$\frac{2 \mu_0 \pi^{1 / 2}}{\mathrm{BA}^{3 / 2}}$

$\frac{\mathrm{BA}^{3 / 2}}{\mu_0 \pi}$

$\frac{2 \mathrm{~B} \mathrm{~A}^{3 / 2}}{\mu_0 \pi^{1 / 2}}$

$\frac{\mathrm{B} \mathrm{A}^2}{\mu_0 \pi}$

MHT CET 2024 2nd May Morning Shift

MCQ (Single Correct Answer)

-0

Two identical current carrying coils with same centre are placed with their planes perpendicular to each other. If current $\mathrm{I}=\sqrt{2} \mathrm{~A}$ and radius of the coil is $R=1 \mathrm{~m}$, then magnetic field at centre is equal to ( $\mu_0=$ permeability of free space)

$\mu_0$

$\frac{\mu_0}{2}$

$2 \mu_0$

$\sqrt{2} \mu_0$

MHT CET 2023 14th May Evening Shift

MCQ (Single Correct Answer)

-0

Figure shows two semicircular loops of radii $$R_1$$ and $$R_2$$ carrying current $I$. The magnetic field at the common centre '$$\mathrm{O}$$' is

MHT CET 2023 14th May Evening Shift Physics - Moving Charges and Magnetism Question 71 English

$$\frac{\mu_0 \mathrm{I}}{4}\left(\frac{1}{\mathrm{R}_1}+\frac{1}{\mathrm{R}_2}\right)$$

$$\frac{\mu_0 \mathrm{I}}{4}\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right)$$

$$\frac{\mu_0 \mathrm{I}}{2 \pi}\left(\frac{1}{\mathrm{R}_1}+\frac{1}{\mathrm{R}_2}\right)$$

$$\frac{\mu_0 I}{2 \pi}\left(\frac{1}{R_1}-\frac{1}{R_2}\right)$$

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