MHT CET 2025 19th April Evening Shift | Moving Charges and Magnetism Question 26 | Physics

Bohr model is applied to a particle of mass m and charge $q$ is moving in a plane under the influence of a transverse magnetic field (B). The energy of the charged particle in the second level will be ( $\mathrm{h}=$ Planck's constant)

$\frac{\mathrm{qBh}}{\pi \mathrm{m}}$

$\frac{\mathrm{q}^2 \mathrm{~B}^2 \mathrm{~h}^2}{4 \pi \mathrm{~m}}$

$\frac{\mathrm{qBh}}{2 \pi \mathrm{~m}}$

$\frac{2 q \mathrm{Bh}}{\pi m}$

MHT CET 2025 19th April Evening Shift

MCQ (Single Correct Answer)

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Two long conductors separated by a distance ' d ' carry currents ' $\mathrm{I}_1$ ' and ' $\mathrm{I}_2$ ' in the same directions. They exert a force ' $F$ ' on each other. The distance between them is increased to ' 3 d '. If new repulsive force of magnitude ' $\frac{2}{3} \mathrm{~F}$ ' is found between these conductors, the required change in the magnitude and direction of one of the currents in the conductor is respectively [length of the conductors is constant]

same, reversed.

twice, reversed.

thrice, same.

twice, same.

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

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Two long parallel wires carrying currents 4 A and 3 A in opposite directions are placed at a distance of 5 cm from each other. A point P is at equidistance from both the wires such that the line joining the point P to the wires are perpendicular to each other. The magnitude of magnetic field at point $P$ is ( $\mu_0=$ permeability of free space $=4 \pi \times 10^{-7}$ SI unit)

$4 \times 10^{-5} \mathrm{~T}$

$\sqrt{2} \times 10^{-5} \mathrm{~T}$

$2 \times 10^{-5} \mathrm{~T}$

$2 \sqrt{2} \times 10^{-5} \mathrm{~T}$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

The ratio of angular momentum $L$ of an electron to the magnetic dipole moment $\overrightarrow{\mathrm{m}}_{\text {orb }}$ is ( ' $m$ ' is mass of electron, ' $e$ ' is charge on electron)

$\frac{\mathrm{e}}{\mathrm{m}}$

$\frac{2 m}{e}$

$\frac{\mathrm{e}}{2 \mathrm{~m}}$

$\frac{\mathrm{m}}{\mathrm{e}}$

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