1
MHT CET 2021 20th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

A random variable X has the following probability distribution

$$\mathrm{X=x}$$ 0 1 2 3 4 5 6 7
$$\mathrm{P[X=x]}$$ 0 $$\mathrm{k}$$ $$\mathrm{2k}$$ $$\mathrm{2k}$$ $$\mathrm{3k}$$ $$\mathrm{k^2}$$ $$\mathrm{2k^2}$$ $$\mathrm{7k^2+k}$$

then F(4) =

A
$$\frac{3}{10}$$
B
$$\frac{1}{10}$$
C
$$\frac{7}{10}$$
D
$$\frac{4}{5}$$
2
MHT CET 2021 20th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

Rajesh has just bought a VCR from Maharashtra Electronics and the shop offers after sales service contract for Rs. 1000 for the next five years. Considering the experience of VCR users, the following distribution of maintenance expenses for the next five years is formed.

Expenses 0 500 1000 1500 2000 2500 3000
Probability 0.35 0.25 0.15 0.10 0.08 0.05 0.02

The expected value of maintenance cost is :

A
Rs. 800
B
Rs. 770
C
Rs. 700
D
Rs. 900
3
MHT CET 2021 20th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$X \sim B(4, p)$$ and $$P(X=0)=\frac{16}{81}$$, then $$P(X=4)=$$

A
$$\frac{1}{81}$$
B
$$\frac{1}{16}$$
C
$$\frac{1}{8}$$
D
$$\frac{1}{27}$$
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