MHT CET 2023 10th May Evening Shift | Probability Question 90 | Mathematics

A fair die is tossed twice in succession. If $$\mathrm{X}$$ denotes the number of sixes in two tosses, then the probability distribution of $$\mathrm{X}$$ is given by

$$\mathrm{X=}x$$	0	1	2
$$\mathrm{P(X=}x)$$	$$\frac{25}{36}$$	$$\frac{1}{36}$$	$$\frac{5}{18}$$

$$\mathrm{X=}x$$	0	1	2
$$\mathrm{P(X=}x)$$	$$\frac{5}{18}$$	$$\frac{1}{36}$$	$$\frac{25}{36}$$

$$\mathrm{X=}x$$	0	1	2
$$\mathrm{P(X=}x)$$	$$\frac{25}{36}$$	$$\frac{5}{18}$$	$$\frac{1}{36}$$

$$\mathrm{X=}x$$	0	1	2
$$\mathrm{P(X=}x)$$	$$\frac{5}{18}$$	$$\frac{25}{36}$$	$$\frac{1}{36}$$

MHT CET 2023 10th May Morning Shift

MCQ (Single Correct Answer)

-0

For a binomial variate $$\mathrm{X}$$ with $$\mathrm{n}=6$$ if $$P(X=4)=\frac{135}{2^{12}}$$, then its variance is

$$\frac{8}{9}$$

$$\frac{1}{4}$$

$$\frac{9}{8}$$

MHT CET 2023 10th May Morning Shift

MCQ (Single Correct Answer)

-0

The p.d.f. of a discrete random variable is defined as $$\mathrm{f}(x)=\left\{\begin{array}{l} \mathrm{k} x^2, 0 \leq x \leq 6 \\ 0, \text { otherwise } \end{array}\right.$$

Then the value of $$F(4)$$ (c.d.f) is

$$\frac{30}{91}$$

$$\frac{30}{97}$$

$$\frac{15}{47}$$

$$\frac{15}{97}$$

MHT CET 2023 10th May Morning Shift

MCQ (Single Correct Answer)

-0

A player tosses 2 fair coins. He wins ₹5 if 2 heads appear, ₹ 2 if one head appears and ₹ 1 if no head appears. Then the variance of his winning amount in ₹ is :

$$\frac{5}{2}$$

$$\frac{9}{4}$$

$$\frac{17}{2}$$

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