MHT CET 2019 2nd May Evening Shift | Moving Charges and Magnetism Question 145 | Physics

A circular coil of wire consisting of 100 turns each of radius 9 cm carries a current of 0.4 A . The magnitude of the magnetic field at the centre of coil is $\left[\mu_0=12.56 \times 10^{-7} \mathrm{SI}\right.$ Unit]

$2.4 \times 10^{-11} \mathrm{~T}$

$2.79 \times 10^{-5} \mathrm{~T}$

$2.79 \times 10^{-4} \mathrm{~T}$

$2.79 \times 10^{-3} \mathrm{~T}$

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

The magnetic dipole moment of a short magnetic dipole at a distant point along the equator of magnet has a magnitude of ' $X$ ' in SI units. If the distance between the point and the magnet is halved then the magnitude of dipole moment will be

$2 x$

$\frac{1}{2} x$

$X$

$\frac{1}{8} x$

MHT CET 2019 2nd May Morning Shift

MCQ (Single Correct Answer)

-0

Two parallel conductors carrying unequal currents in the same direction ............

neither attract nor repel each other

repel each other

attract each other

will have rotational motion.

MHT CET 2019 2nd May Morning Shift

MCQ (Single Correct Answer)

-0

The magnitude of the magnetic induction at a point on the axis at a large distance ( $r$ ) from the centre of a circular coil of ' $n$ ' turns and area ' $A$ ' carrying current ( $I$ ) is given by

$B_{\text {axis }}=\frac{\mu_0}{4 \pi} \cdot \frac{n A}{1 r^3}$

$B_{\text {axis }}=\frac{\mu_0}{4 \pi} \cdot \frac{2 n l A}{r^3}$

$B_{\text {axis }}=\frac{\mu_0}{4 \pi} \cdot \frac{2 n l}{A r^3}$

$B_{\text {axis }}=\frac{\mu_0}{4 \pi} \cdot \frac{n l A}{r^3}$

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