1
GATE EE 2026
MCQ (Single Correct Answer)
+2
-0

The digital circuit shown has 3 inputs $(x, y$ and $z)$.

GATE EE 2026 Digital Electronics - Boolean Algebra Question 1 English

The simplified logical expression for the output (OUT) is:

A

$\bar{x} \bar{y} \bar{z}$

B

0

C

$\bar{x}(y+z)$

D

1

2
GATE EE 2025
MCQ (Single Correct Answer)
+2
-0.67

A Boolean function is given as

$$ f=(\bar{u}+\bar{v}+\bar{w}+\bar{x}) \cdot(\bar{u}+\bar{v}+\bar{w}+x) \cdot(\bar{u}+v+\bar{w}+\bar{x}) \cdot(\bar{u}+v+\bar{w}+x) $$

The simplified form of this function is represented by

A
GATE EE 2025 Digital Electronics - Boolean Algebra Question 2 English Option 1
B
GATE EE 2025 Digital Electronics - Boolean Algebra Question 2 English Option 2
C
GATE EE 2025 Digital Electronics - Boolean Algebra Question 2 English Option 3
D
GATE EE 2025 Digital Electronics - Boolean Algebra Question 2 English Option 4
3
GATE EE 2017 Set 1
MCQ (Single Correct Answer)
+2
-0.6
The logical gate implemented using the circuit shown below where $${V_1}$$ and $${V_2}$$ are inputs (with $$0$$ $$V$$ as digital $$0$$ and $$5$$ $$V$$ as digital $$1$$) and $${V_{OUT}}$$ is the output is GATE EE 2017 Set 1 Digital Electronics - Boolean Algebra Question 5 English
A
$$NOT$$
B
$$NOR$$
C
$$NAND$$
D
$$XOR$$
4
GATE EE 2004
MCQ (Single Correct Answer)
+2
-0.6
The simplified form of the Boolean expression $$Y = \left( {\overline A BC + D} \right)\left( {\overline A D + \overline B \overline C } \right)$$ can be written as
A
$$\overline A D + \overline B \overline C D$$
B
$$AD + B\overline C D$$
C
$$\left( {\overline A + D} \right)\left( {\overline B C + \overline D } \right)$$
D
$$A\overline D + BC\overline D $$

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