1
GATE ME 1995
MCQ (Single Correct Answer)
+1
-0.3
Consider a refrigerator and a heat pump working on the reversed Carnot cycle between the same temperature limits. Which of the following is correct?
A
$$COP$$ refrigerator $$= COP$$ of heat pump
B
$$COP$$ of refrigerator $$= COP$$ of heat pump $$+ 1$$
C
$$COP$$ of refrigerator $$= COP$$ of heat pump $$- 1$$
D
$$COP$$ of refrigerator $$=$$ inverse $$COP$$ of heat pump
2
GATE ME 1995
Fill in the Blanks
+1
-0
In the case of a refrigeration system undergoing an irreversible cycle, $$\oint {{{SQ} \over T}} $$ is _____________$$\left( { < 0/ = 0/ > 0} \right)$$
3
GATE ME 1994
True or False
+1
-0
Any thermodynamic cycle operating between two temperature limits is reversible if the product of efficiency when operating as a heat engine and the coefficient of performance when operating as a refrigeration is equal to $$1.$$
A
TRUE
B
FALSE
4
GATE ME 1993
MCQ (Single Correct Answer)
+1
-0.3
A reversible heat transfer demands:
A
The temperature difference causing heat transfer tends to zero
B
The system receiving heat must be at a constant temperature.
C
The system transferring out heat must be at a constant temperature.
D
Both interacting systems must be at constant temperatures
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