First Law of Thermodynamics ยท Thermodynamics ยท GATE ME
Marks 1
Marks 2
Consider a fully adiabatic piston-cylinder arrangement as shown in the figure. The piston is massless and cross-sectional area of the cylinder is ๐ด. The fluid inside the cylinder is air (considered as a perfect gas), with ฮณ being the ratio of the specific heat at constant pressure to the specific heat at constant volume for air. The piston is initially located at a position ๐ฟ1. The initial pressure of the air inside the cylinder is ๐1 โซ ๐0, where ๐0 is the atmospheric pressure. The stop S1 is instantaneously removed and the piston moves to the position ๐ฟ2, where the
equilibrium pressure of air inside the cylinder is ๐2 โซ ๐0.
What is the work done by the piston on the atmosphere during this process?
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A rigid tank of volume of 8 m3 is being filled up with air from a pipeline connected through a valve. Initially the valve is closed and the tank is assumed to be completely evacuated. The air pressure and temperature inside the pipeline are maintained at 600 kPa and 306 K, respectively. The filling of the tank begins by opening the valve and the process ends when the tank pressure is equal to the pipeline pressure. During the filling process, heat loss to the surrounding is 1000 kJ. The specific heats of air at constant pressure and at constant volume are 1.005 kJ/kg.K and 0.718 kJ/kg.K, respectively. Neglect changes in kinetic energy and potential energy.
The final temperature of the tank after the completion of the filling process is ________ K (round off to the nearest integer).
(Take the sign convention such that work done on the system is negative)
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The rate of heat loss from the turbine per $$kg$$ of steam flow rate is $$5$$ $$kW.$$ Neglecting changes in potential energy of steam, the power developed in $$kW$$ by the steam turbine per $$kg$$ of steam flow rate, is
The exit temperature of the air is
The exit area of the nozzle in $$c{m^2}$$ is
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The mass flow rate of air through the nozzle in $$kg/s$$ is
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The density of air in $$kg/{m^3}$$ at the nozzle exit is
Assume that the gases behave as ideal gases. Calculate the increase in entropy of the contents of the cylinder. Universal gas constant equal to $$8314.3$$ $$J/kmol$$ $$K.$$
Marks 5
$${T_1} = 330\,K,\,\,{T_2} = 440\,K;\,\,{U_1} = 170\,kJ,\,\,$$
$$\,{U_2} = 190\,kJ;\,\,{H_1} = 220{\,_{}}kJ,\,\,{H_2} = 247\,kJ,$$
and $${S_1} = 0.23\,kJ/K$$ and $${S_2} = 0.3\,kJ/K$$ where $$T, U, H$$ and $$S$$ represent temperature, internal energy, enthalpy and entropy respectively.