Scheduling · Industrial Engineering · GATE ME

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Marks 2

1

Four jobs are on order in a factory. As on day 20 of the production calendar, the corresponding due date and work remaining to complete these jobs (in days) are given in the table below.

$$ \begin{array}{|c|c|c|} \hline \text { Job } & \text { Due date } & \text { Work remaining (in days) } \\ \hline \text { M } & 26 & 5 \\ \hline \text { N } & 24 & 10 \\ \hline \text { O } & 28 & 10 \\ \hline \text { P } & 31 & 5 \\ \hline \end{array} $$

Which job(s) has/have critical ratio less than unity?

GATE ME 2026
2

Parts P1 - P7 are machined first on a milling machine and then polished at a separate machine. Using the information in the following table, the minimum total completion time required for carrying out both the operations for all 7 parts is _______ hours.

Part

Milling (hours)

Polishing (hours)

P1

8

6

P2

3

2

P3

3

4

P4

4

6

P5

5

7

P6

6

4

P7

2

1

GATE ME 2022 Set 2
3
Following data refers to the jobs $$(P, Q, R, S)$$ which have arrived at a machine for scheduling. The shortest possible average flow time is ___________ days. GATE ME 2017 Set 1 Industrial Engineering - Scheduling Question 7 English
GATE ME 2017 Set 1
4
Four jobs are to be processed on a machine as per data listed in the table. GATE ME 2010 Industrial Engineering - Scheduling Question 8 English

Using the Shortest Processing Time $$(SPT)$$ rule, total tardiness is

GATE ME 2010
5
Four jobs are to be processed on a machine as per data listed in the table. GATE ME 2010 Industrial Engineering - Scheduling Question 9 English

If the Earliest Due Date $$(EDD)$$ rule is used to sequence the jobs, the number of jobs delayed is

GATE ME 2010
6
Six jobs arrived in a sequence as given below: GATE ME 2009 Industrial Engineering - Scheduling Question 10 English

Average flow time (in days) for the above jobs using Shortest Processing Time rule is

GATE ME 2009
7
A set of $$5$$ jobs is to be processed on a single machine. The processing time (in days) is given in the table below. The holding cost for each job is Rs. $$K$$ per day. GATE ME 2008 Industrial Engineering - Scheduling Question 11 English

A schedule that minimizes the total inventory cost is

GATE ME 2008

Marks 5