Linear Programming ยท Industrial Engineering ยท GATE ME
Marks 1
Which one of the options given represents the feasible region of the linear programming model:
๐๐๐ฅ๐๐๐๐ง๐ 45๐1 + 60๐2
๐1 โค 45
๐2 โค 50
10๐1 + 10๐2 โฅ 600
25๐1 + 5๐2 โค 750
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Marks 2
At the current basic feasible solution (bfs) $v_0 (v_0 \in \mathbb{R}^5)$, the simplex method yields the following form of a linear programming problem in standard form:
minimize $z = -x_1 - 2x_2$
s.t.
$x_3 = 2 + 2x_1 - x_2$
$x_4 = 7 + x_1 - 2x_2$
$x_5 = 3 - x_1$
$x_1, x_2, x_3, x_4, x_5 \geq 0$
Here the objective function is written as a function of the non-basic variables. If the simplex method moves to the adjacent bfs $v_1 (v_1 \in \mathbb{R}^5)$ that best improves the objective function, which of the following represents the objective function at $v_1$, assuming that the objective function is written in the same manner as above?
A manufacturing unit produces two products Pl and P2. For each piece of P1 and P2, the table below provides quantities of materials M1, M2, and M3 required, and also the profit earned. The maximum quantity available per day for M1, M2 and M3 is also provided. The maximum possible profit per day is โน ______
M1 | M2 | M3 | Profit per piece ( โน) | |
---|---|---|---|---|
P1 | 2 | 2 | 0 | 150 |
P2 | 3 | 1 | 2 | 100 |
Maximum quantity available per day | 70 | 50 | 40 |
Subject to $$\,\,\,\,\,\,\,\,\,\,{x_1} + 2{x_2} \le 10,$$
$$\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{x_1} - {x_2} \le 8, \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{x_1},{x_2} \ge 0 \cr} $$
In the starting simplex tableau, $${x_1}$$ and $${x_2}$$ are non-basic variables and the value of $$Z$$ is zero. The value of $$Z$$ in the next simplex tableau is __________________.
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Subject to
$$\eqalign{ & 12{x_1} + 4{x_2} \ge 36 \cr & 12{x_1} - 6{x_2} \le 24 \cr & \,\,\,\,\,\,\,\,\,{x_1},\,\,{x_2} \ge 0 \cr} $$
The above linear programming problem has
$$\eqalign{ & Maximize\,\,\,\,\,Z = 3{x_1} + 2{x_2} \cr & Subject\,\,to\,\,\,\, - 2{x_1} + 3{x_2} \le 9 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{x_1} - 5{x_2} \ge - 20 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{x_1},\,\,{x_2} \ge 0 \cr} $$
The above problem has
$$\eqalign{ & {x_1} + {x_2} \le 8, \cr & {x_1} + 2{x_2} \le 4, \cr & {x_1} \ge 0,{x_2} \ge 0, \cr} $$
The maximum value of the objective function is ________________.
$$\eqalign{ & Maximize\,\,\,\,3x + 7y \cr & Subject\,\,to\,\,\,3x + 7y \le 10 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,4x + 6y \le 8 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x,\,\,y \ge 0 \cr} $$
It has ..............
The manufacturer can make a maximum profit of Rs.
The unit worth of resource $${R_2}$$. i.e. dual price of resource $${R_2}$$ in Rs. per $$kg$$ is
Maximize: $$Z = 3{x_1} + 2{x_2}$$
$$\,\,$$ Subject $$\,\,$$ to
$$\eqalign{
& \,\,\,\,\,\,\,{x_1} \le 4 \cr
& \,\,\,\,\,\,\,{x_2} \le 6 \cr
& 3{x_1} + 2{x_2} \le 18 \cr
& {x_1} \ge 0,\,\,{x_2} \ge 0 \cr} $$
Max $$4x$$ + $$6y$$
Subject to
$$\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,3x + 2y \le 6 \cr & \,\,\,\,\,\,\,\,\,\,\,2x + 3y \le 6 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x,y \ge 0 \cr} $$
The dual for the $$LP$$ is
Max $$4x$$ + $$6y$$
Subject to
$$\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,3x + 2y \le 6 \cr & \,\,\,\,\,\,\,\,\,\,\,2x + 3y \le 6 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x,y \ge 0 \cr} $$
After introducing slack variables $$s$$ and $$t$$, the initial basic feasible solution is represented by the table below (basic variables are $$s=6$$ $$t=6,$$ and the objective function value is $$0$$).
After some simplex iterations, the following table is obtained
From this, one can conclude that
If an additional constraint $${x_1} + {x_2} \le 5$$ is added, the optimal solution is
Let $${y_1}$$ and $${y_2}$$ be the decision variables of the dual and $${v_1}$$ and $${v_2}$$ be the slack variables of the dual of the given linear programming problem. The optimum dual variables are
The maximum profit which can meet the constraints is
Marks 5
$$(a)$$ Set up the problem as a Linear Program
$$(b)$$ Determine the optimum product mix for maximizing the profit.
$$(c)$$ What is the maximum profit?
$$(d)$$ If the profit of each table drops to Rs.200 per unit, what is the optimal mix and profit?
$$\eqalign{ & Maximize\,\,\,\,\,\,4{x_1} + 6{x_2} + {x_3} \cr & Subject\,\,to\,\,\,\,\,\,2{x_1} - {x_2} + 3{x_3}\, \le 5 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{x_1},{x_2},{x_3} \ge 0 \cr} $$
$$(a)$$$$\,\,\,\,\,\,\,$$ What is the solution to the above problem?
$$(b)$$$$\,\,\,\,\,\,\,$$ Add the constant $${x_2} \le 2$$ to the simplex table of part $$(a)$$ and find the solution.