1
GATE CSE 2014 Set 3
Numerical
+2
-0
An operating system uses $$shortest$$ $$remaining$$ $$time$$ $$first$$ scheduling algorithm for pre-emptive scheduling of processes. Consider the following set of processes with their arrival times and $$CPU$$ burst times (in milliseconds):
Process | Arrival Time | Burst Time |
---|---|---|
P1 | 0 | 12 |
P2 | 2 | 4 |
P3 | 3 | 6 |
P4 | 8 | 5 |
The average waiting time (in milliseconds) of the processes is ________.
Your input ____
2
GATE CSE 2014 Set 1
Numerical
+2
-0
Consider the following set of processes that need to be scheduled on a single $$CPU.$$ All the times are given in milliseconds.
Process Name | Arrival Time | Execution Time |
---|---|---|
A | 0 | 6 |
B | 3 | 2 |
C | 5 | 4 |
D | 7 | 6 |
E | 10 | 3 |
Using the $$shortest$$ $$remaining$$ $$time$$ $$first$$ scheduling algorithm, the average process turnaround time (in $$msec$$) is _______.
Your input ____
3
GATE CSE 2012
MCQ (Single Correct Answer)
+2
-0.6
Consider the $$3$$ processes, $$P1,$$ $$P2$$ and $$P3$$ shown in the table.
Process | Arrival Time | Time Units Required |
---|---|---|
P1 | 0 | 5 |
P2 | 1 | 7 |
P3 | 3 | 4 |
The completion order of the $$3$$ processes under the policies $$FCFS$$ and $$RR2$$ (round robin scheduling with $$CPU$$ quantum of $$2$$ time units) are
4
GATE CSE 2011
MCQ (Single Correct Answer)
+2
-0.6
Consider the following table of arrival time and burst time for three processes $$P0,P1$$ and $$P2$$.
Process | Arrival Time | Burst Time |
---|---|---|
P0 | 0 ms | 9 ms |
P1 | 1 ms | 4 ms |
P2 | 2 ms | 9 ms |
The pre-emptive shortest job first scheduling algorithm is used. Scheduling is carried out only a arrival or completion of processes. What is the average waiting time for the three processes?
Questions Asked from Process Concepts and Cpu Scheduling (Marks 2)
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