1
GATE EE 2013
MCQ (Single Correct Answer)
+2
-0.6
A voltage $$1000\sin \omega t$$ Volts is applied across $$YZ.$$ Assuming ideal diodes, the voltage measured across $$WX$$ in Volts is GATE EE 2013 Analog Electronics - Diode Circuits and Applications Question 14 English
A
$$\sin \omega t$$
B
$$\left( {\sin \omega t + \left| {\sin \omega t} \right|} \right)/2$$
C
$$\left( {\sin \omega t - \left| {\sin \omega t} \right|} \right)/2$$
D
$$0$$ for all $$t$$
2
GATE EE 2013
MCQ (Single Correct Answer)
+2
-0.6
In the circuit shown below, the knee current of the ideal Zener diode is $$10$$ $$mA.$$ To maintain $$5 V$$ across $${R_L}$$, the minimum value of $${R_L}$$ in $$\Omega $$ and the minimum power rating of the Zener diode in $$mW$$ respectively are GATE EE 2013 Analog Electronics - Diode Circuits and Applications Question 15 English
A
$$125$$ and $$125$$
B
$$125$$ and $$250$$
C
$$250$$ and $$125$$
D
$$250$$ and $$250$$
3
GATE EE 2011
MCQ (Single Correct Answer)
+2
-0.6
A clipper Circuit is shown below GATE EE 2011 Analog Electronics - Diode Circuits and Applications Question 16 English

Assuming forward voltage drops of the diodes to be $$0.7V,$$ the input-output transfer characteristics of the circuit is

A
GATE EE 2011 Analog Electronics - Diode Circuits and Applications Question 16 English Option 1
B
GATE EE 2011 Analog Electronics - Diode Circuits and Applications Question 16 English Option 2
C
GATE EE 2011 Analog Electronics - Diode Circuits and Applications Question 16 English Option 3
D
GATE EE 2011 Analog Electronics - Diode Circuits and Applications Question 16 English Option 4
4
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
In the voltage doubler circuit shown in figure, the switch $$' S '$$ is closed at $$t=0$$. Assuming diodes $${D_1}$$ & $${D_2}$$ to be ideal, load resistance to be infinite and initial capacitor voltages to be zero, the steady state voltage across capacitors $${C_1}$$ & $${C_2}$$ will be GATE EE 2008 Analog Electronics - Diode Circuits and Applications Question 6 English
A
$${V_{c1}} = 10V,\,\,{V_{c2}} = 5V$$
B
$${V_{c1}} = 10V,\,\,{C_{c2}} = -5V$$
C
$${V_{c1}} = 5V,\,\,{V_{c2}} = 10V$$
D
$${V_{c1}} = 5V,\,\,{V_{c2}} = -10V$$
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