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1
IIT-JEE 1999 Screening
MCQ (Single Correct Answer)
+2
-0.5
A particle free to move along the x-axis has potential energy given by $$U\left( x \right) = k\left[ {1 - \exp \left( { - {x^2}} \right)} \right]$$ for $$ - \infty \le x \le - \infty $$, where k is a positive constant of appropriate dimensions. Then
A
at points away from the origin, the particle is in unstable equilibrium
B
for any finite nonzero value of x, there is a force directed away from the origin
C
if its total mechanical energy is $${k \over 2}$$, it has its minimum kinetic energy at the origin
D
for small displacement from x = 0, the motion is simple harmonic

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