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1

AIPMT 2009

MCQ (Single Correct Answer)
The symbolic representation of four logic gates are given below



The logic symbols for OR, NOT and NAND gates are respectively
A
(iv), (i), (iii)
B
(iv), (ii), (i)
C
(i), (iii), (iv)
D
(iii), (iv), (ii)

Explanation

OR gate, NOT gate and NAND gates are (iv), (ii) and (i) respectively.
2

AIPMT 2008

MCQ (Single Correct Answer)
If the lattice parameter for a crystalline structure is 3.6 $$\mathop A\limits^ \circ $$, then the atomic radius in fcc crystal is
A
2.92 $$\mathop A\limits^ \circ $$
B
1.27 $$\mathop A\limits^ \circ $$
C
1.81 $$\mathop A\limits^ \circ $$
D
2.10 $$\mathop A\limits^ \circ $$

Explanation

The atomic radius in a f.c.c. crystal is = $${a \over {2\sqrt 2 }}$$

$$ \therefore $$ Atomic radius = $${{3.6} \over {2\sqrt 2 }}$$ = 1.27 $$\mathop A\limits^ \circ $$
3

AIPMT 2008

MCQ (Single Correct Answer)
The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain without feedback will be
A
1.25
B
100
C
90
D
10

Explanation

Negative feedback is applied to reduce the output voltage of an amplifier. If there is no negative feedback, the value of output voltage could be very high. In the options given, the maximum value of voltage gain is 100. Hence it is the correct option.
4

AIPMT 2008

MCQ (Single Correct Answer)
A p-n photodiode is made of a material with a band gap of 2.0 eV. The minimum frequency of the radiation that can be absorbed by the material is nearly
A
1 $$ \times $$ 1014 Hz
B
20 $$ \times $$ 1014 Hz
C
10 $$ \times $$ 1014 Hz
D
5 $$ \times $$ 1014 Hz

Explanation

Energy gap Eg = 2.0 eV

Eg = 2.0 × 1.6 × 10–19 J

Eg = hf

f = frequency of radiation

$$ \therefore $$ f = $${{{E_g}} \over h}$$

= $${{3.2 \times {{10}^{ - 19}}} \over {6.625 \times {{10}^{ - 34}}}}$$

= 5 $$ \times $$ 1014 Hz

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