Capacitor · Physics · NEET
MCQ (Single Correct Answer)
A $$12 \mathrm{~pF}$$ capacitor is connected to a $$50 \mathrm{~V}$$ battery, the electrostatic energy stored in the capacitor in $$\mathrm{nJ}$$ is
The capacitance of a capacitor with charge $$q$$ and a potential difference $$V$$ depends on
The steady state current in the circuit shown below is :
In the following circuit, the equivalent capacitance between terminal A and terminal B is :
If the plates of a parallel plate capacitor connected to a battery are moved close to each other, then
A. the charge stored in it, increases.
B. the energy stored in it, decreases.
C. its capacitance increases.
D. the ratio of charge to its potential remains the same.
E. the product of charge and voltage increases.
Choose the most appropriate answer from the options given below:
The equivalent capacitance of the arrangement shown in figure is:
To produce an instantaneous displacement current of $$2 \mathrm{~mA}$$ in the space between the parallel plates of a capacitor of capacitance $$4 ~\mu \mathrm{F}$$, the rate of change of applied variable potential difference $$\left(\frac{\mathrm{dV}}{\mathrm{dt}}\right)$$ must be :-
The equivalent capacitance of the system shown in the following circuit is:
The distance between the two plates of a parallel plate capacitor is doubled and the area of each plate is halved. If C is its initial capacitance, its final capacitance is equal to
The effective capacitances of two capacitors are 3 $$\mu$$F and 16 $$\mu$$F, when they are connected in series and parallel respectively. The capacitance of two capacitors are :
A capacitor of capacitance C = 900 pF is charged fully by 100 V battery B as shown in figure (a). Then it is disconnected from the battery and connected to another uncharged capacitor of capacitance C = 900 pF as shown in figure (b). The electrostatic energy stored by the system (b) is
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$$\left( {{\varepsilon _0} = 8.85 \times {{10}^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}}} \right)$$
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