Periodic Table and Periodicity · Chemistry · NEET

The correct decreasing order of atomic radii (pm) of $$\mathrm{Li}, \mathrm{Be}, \mathrm{B}$$ and $$\mathrm{C}$$ is

Match List I with List II :

Identify the correct answer from the options given below :

Arrange the following elements in increasing order of first ionization enthalpy: $$\mathrm{Li}, \mathrm{Be}, \mathrm{B}, \mathrm{C}, \mathrm{N}$$

Choose the correct answer from the options given below:

Arrange the following elements in increasing order of electronegativity:

N, O, F, C, Si

Choose the correct answer from the options given below :

Which of the following is correctly matched?

The correct sequence given below containing neutral, acidic, basic and amphoteric oxide each, respectively, is

The correct order of first ionization enthalpy for the given four elements is :

Decrease in size from left to right in actinoid series is greater and gradual than that in lanthanoid series due to

Fluorine is a stronger oxidising agent than chlorine because :

(a) F-F bond has a low enthalpy of dissociation.

(b) Fluoride ion (F^$$-$$) has high hydration enthalpy.

(c) Electron gain enthalpy of fluorine is less negative than chlorine.

(d) Fluorine has a very small size.

Choose the most appropriate answer from the options given :

If first ionization enthalpies of elements X and Y are 419 kJ mol^$$-$$1 and 590 kJ mol^$$-$$1, respectively and second ionization enthalpies of X and Y are 3069 kJ mol^$$-$$1 and 1145 kJ mol^$$-$$1, respectively. Then correct statement is :

The IUPAC name of an element with atomic number 119 is

Gadolinium has a low value of third ionisation enthalpy because of