NEW
New Website Launch
Experience the best way to solve previous year questions with mock tests (very detailed analysis), bookmark your favourite questions, practice etc...
1

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)
If in a p-n junction, a square input signal of 10 V is applied, as shown,



then the output across RL will be
A
B
C
D

Explanation

Here P-N junction diode rectifies half of the ac wave i.e., acts as half wave rectifier.
During + ve half cycle Diode is forward biased output across RL will be

During –ve half cycle Diode is reverse biased output will not obtained.
2

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)
Which logic gate is represented by the following combination of logic gates ?

A
AND
B
NOR
C
OR
D
NAND

Explanation

The Boolean expression of this arrangement is

Y = $$\overline {\overline A + \overline B } $$ = $$\overline{\overline A} + \overline{\overline B} $$ = A.B

Thus, the combination represents AND gate.
3

AIPMT 2015

MCQ (Single Correct Answer)
In the given figure, a diode D is connected to an external resistance R = 100 $$\Omega $$ and an e.m.f. of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the citcuit will be

A
20 mA
B
35 mA
C
30 mA
D
40 mA

Explanation

Potential difference across resistance R

= 3.5 – 0.5 = 3.0 V

Current in circuit, I = V/R = 3/100 = 30 mA
4

AIPMT 2015

MCQ (Single Correct Answer)
The input signal given to a CE amplifier having a voltage gain of 150 is Vi = 2cos(15t + $${\pi \over 3}$$). The corresponding output signal will be
A
2cos$$\left( {15t + {{5\pi } \over 6}} \right)$$
B
300cos$$\left( {15t + {{4\pi } \over 3}} \right)$$
C
300cos$$\left( {15t + {{\pi } \over 3}} \right)$$
D
75cos$$\left( {15t + {{2\pi } \over 3}} \right)$$

Explanation

Given, Vi = 2cos(15t + $${\pi \over 3}$$)

and Voltage gain AV = 150

For CE transistor phase difference between input and output signal is $$\pi $$ = 180o

Using formula, AV = $${{{V_0}} \over {{V_i}}}$$

$$ \Rightarrow $$ V0 = AV $$ \times $$ Vi

= 150$$ \times $$2cos(15t + $${\pi \over 3}$$ + $$\pi $$)

= 300cos$$\left( {15t + {{4\pi } \over 3}} \right)$$

Joint Entrance Examination

JEE Main JEE Advanced WB JEE

Graduate Aptitude Test in Engineering

GATE CSE GATE ECE GATE EE GATE ME GATE CE GATE PI GATE IN

Medical

NEET

CBSE

Class 12