1
NEET 2016 Phase 1
MCQ (Single Correct Answer)
+4
-1
Change Language
Consider the junction diode as ideal. The value of current flowing through AB is

NEET 2016 Phase 1 Physics - Semiconductor Electronics Question 108 English
A
10$$-$$1 A
B
10$$-$$3 A
C
0 A
D
10$$-$$2 A
2
AIPMT 2015
MCQ (Single Correct Answer)
+4
-1
Change Language
In the given figure, a diode D is connected to an external resistance R = 100 $$\Omega $$ and an e.m.f. of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the citcuit will be

AIPMT 2015 Physics - Semiconductor Electronics Question 106 English
A
20 mA
B
35 mA
C
30 mA
D
40 mA
3
AIPMT 2015
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The input signal given to a CE amplifier having a voltage gain of 150 is Vi = 2cos(15t + $${\pi \over 3}$$). The corresponding output signal will be
A
2cos$$\left( {15t + {{5\pi } \over 6}} \right)$$
B
300cos$$\left( {15t + {{4\pi } \over 3}} \right)$$
C
300cos$$\left( {15t + {{\pi } \over 3}} \right)$$
D
75cos$$\left( {15t + {{2\pi } \over 3}} \right)$$
4
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Change Language
If in a p-n junction, a square input signal of 10 V is applied, as shown,

AIPMT 2015 Cancelled Paper Physics - Semiconductor Electronics Question 104 English

then the output across RL will be
A
AIPMT 2015 Cancelled Paper Physics - Semiconductor Electronics Question 104 English Option 1
B
AIPMT 2015 Cancelled Paper Physics - Semiconductor Electronics Question 104 English Option 2
C
AIPMT 2015 Cancelled Paper Physics - Semiconductor Electronics Question 104 English Option 3
D
AIPMT 2015 Cancelled Paper Physics - Semiconductor Electronics Question 104 English Option 4

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