Aldehydes, Ketones and Carboxylic Acids · Chemistry · NEET
MCQ (Single Correct Answer)
Select the incorrect reaction among the following :
Identify the correct reagents that would bring about the following transformation.
Match List I with List II.
List I (Reaction) |
List II (Reagents/Condition) |
||
---|---|---|---|
A. | ![]() |
I. | ![]() |
B. | ![]() |
II. | CrO$$_3$$ |
C. | ![]() |
III. | KMnO$$_4$$/KOH, $$\Delta$$ |
D. | ![]() |
IV. | (i) O$$_3$$ (ii) Zn-H$$_2$$O |
Choose the correct answer from the options given below:
For the given reaction:
'P' is
Consider the given reaction:
$$\mathrm{CH}_3 \mathrm{COCH}_3 \stackrel{\text { dil } \mathrm{Ba}(\mathrm{OH})_2}{\longrightarrow} \text { ''X" }$$
The functional groups present in compound "$$\mathrm{X}$$" are:
Identify 'X' in above reactions
The following conversion is known as:
Reagents which can be used to convert alcohols to carboxylic acids, are
(A) $$\mathrm{CrO}_3-\mathrm{H}_2 \mathrm{SO}_4$$
(B) $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7+\mathrm{H}_2 \mathrm{SO}_4$$
(C) $$\mathrm{KMnO}_4+\mathrm{KOH} / \mathrm{H}_3 \mathrm{O}^{+}$$
(D) $$\mathrm{Cu}, 573 \mathrm{~K}$$
(E) $$\mathrm{CrO}_3,\left(\mathrm{CH}_3 \mathrm{CO}\right)_2 \mathrm{O}$$
Choose the most appropriate answer from the options given below :
The major product formed in the following conversion is ___________.
Complete the following reaction:
[C] is _______.
Identify the major product obtained in the following reaction:
Identify the final product [D] obtained in the following sequence of reactions.
Which of the following reactions is not an example for nucleophilic addition-elimination reaction?
The product formed from the following reaction sequence is
Match List-I with List-II :
List-I (Reaction) |
List-II (Product formed) |
||
---|---|---|---|
(a) | Gabriel synthesis | (i) | Benzaldehyde |
(b) | Kolbe synthesis | (ii) | Ethers |
(c) | Williamson synthesis | (iii) | Primary amines |
(d) | Etard reaction | (iv) | Salicylic acid |
Choose the correct answer from the options given below :
The incorrect method to synthesize benzaldehyde is
Given below are two statements :
Statement I : The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions.
Statement II : The boiling points of aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding.
In the light of the above statements, choose the most appropriate answer from the given below
RMgX + CO2 $$\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{ether}^{dry}} $$ Y $$\buildrel {{H_3}{O^ + }} \over \longrightarrow $$ RCOOH
What is Y in the above reaction?
Match List-I with List-II.
List - I (Products formed) |
List - II (Reaction of carbonyl compound with) |
||
---|---|---|---|
(a) | Cyanohydrin | (i) | NH$$_2$$OH |
(b) | Acetal | (ii) | RNH$$_2$$ |
(c) | Schiff's base | (iii) | Alcohol |
(d) | Oxime | (iv) | HCN |
Choose the correct answer from the options given below
Compound X on reaction with O3 followed by Zn/H2O gives formaldehyde and 2-methyl propanal as products. The compound X is
Which one of the following is not formed when acetone reacts with 2-pentanone in the presence of dilute NaOH followed by heating?
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Consider the above reaction and identify the missing reagent/chemical.
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Choose the correct answer from the options given below.
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Identify A, X, Y and Z.
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is
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with methyl lithium gives which of the following species ?
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RCHO + NH2NH2 $$ \to $$ RCH $$=$$ N $$-$$ NH2
What sort of reaction is it?
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The product A is
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List-I |
List-II |
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---|---|---|---|
(A) | Benzaldehyde | (i) | Phenolphthalein |
(B) | Phthalic anhydride | (ii) | Benzoin condensation |
(C) | Phenyl benzoate | (iii) | Oil of wintergreen |
(D) | Methyl salicylate | (iv) | Fries rearrangement |
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The correct decreasing order of their reactivity towards hydrolysis is
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The structure of D would be
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The structure of D would be
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is
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CH3CHO + HCN $$ \to $$ CH3CH(OH)CN
$$\buildrel {HOH} \over \longrightarrow $$ CH3CH(OH)COOH
an asymmetric centre is generated. The acid obtained would be
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Product $$C$$ would be
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In the above reaction product P is
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are
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