d and f Block Elements · Chemistry · NEET
MCQ (Single Correct Answer)
Baeyer's reagent is :
Which of the following pairs of ions will have same spin only magnetic moment values within the pair?
A. $$\mathrm{Zn}^{2+}, \mathrm{Ti}^{2+}$$
B. $$\mathrm{Cr}^{2+}, \mathrm{Fe}^{2+}$$
C. $$\mathrm{Ti}^{3+}, \mathrm{Cu}^{2+}$$
D. $$\mathrm{V}^{2+}, \mathrm{Cu}^{+}$$
Choose the correct answer from the options given below :
Which of the following set of ions act as oxidising agents?
The UV-visible absorption bands in the spectra of lanthanoid ions are 'X', probably because of the excitation of electrons involving 'Y'. The 'X' and 'Y', respectively, are : Narrow and d and f orbitals
Match List I with List II:
List - I (Block/group in periodic table) |
List - II (Element) |
||
---|---|---|---|
(A) | Lanthanoid | (I) | Ce |
(B) | d-block element | (II) | As |
(C) | p-block element | (III) | Cs |
(D) | s-block element | (IV) | Mn |
Choose the correct answer from the options given below:
Identify the incorrect statement.
'Spin only' magnetic moment is same for which of the following ions?
A. $$\mathrm{Ti}^{3+}$$
B. $$\mathrm{Cr}^{2+}$$
C. $$\mathrm{Mn}^{2+}$$
D. $$\mathrm{Fe}^{2+}$$
E. $$\mathrm{Sc}^{3+}$$
Choose the most appropriate answer from the options given below.
The $$\mathrm{E}^{\circ}$$ value for the $$\mathrm{Mn}^{3+} / \mathrm{Mn}^{2+}$$ couple is more positive than that of $$\mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}$$ or $$\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}$$ due to change of
The pair of lanthanoid ions which are diamagnetic is
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : Ionisation enthalpy increases along each series of the transition elements from left to right. However, small variations occur.
Reason (R) : There is corresponding increase in nuclear charge which accompanies the filling of electrons in the inner d-orbitals.
In the light of the above statements, choose the most appropriate answer from the options given below :
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : Ionisation enthalpies of early actinoids are lower than for early lanthanoids.
Reason (R) : Electrons are entering 5f orbitals in actinoids which experience greater shielding from nuclear charge.
In the light of the above statements, choose the correct answer from the options given below :
The stability of $$\mathrm{Cu}^{2+}$$ is more than $$\mathrm{Cu}^{+}$$ salts in aqueous solution due to -
Which of the following statements are INCORRECT?
A. All the transition metals except scandium form MO oxides which are ionic.
B. The highest oxidation number corresponding to the group number in transition metal oxides is attained in $$\mathrm{Sc}_{2} \mathrm{O}_{3}$$ to $$\mathrm{Mn}_{2} \mathrm{O}_{7}$$.
C. Basic character increases from $$\mathrm{V}_{2} \mathrm{O}_{3}$$ to $$\mathrm{V}_{2} \mathrm{O}_{4}$$ to $$\mathrm{V}_{2} \mathrm{O}_{5}$$.
D. $$\mathrm{V}_{2} \mathrm{O}_{4}$$ dissolves in acids to give $$\mathrm{VO}_{4}^{3-}$$ salts.
E. $$\mathrm{CrO}$$ is basic but $$\mathrm{Cr}_{2} \mathrm{O}_{3}$$ is amphoteric.
Choose the correct answer from the options given below:
Given below are two statements :
Statement I : Cr2+ is oxidising and Mn3+ is reducing in nature.
Statement II : Sc3+ compounds are repelled by the applied magnetic field.
In the light of the above statements, choose the most appropriate answer from the options given below :
Column - I | Column - II |
---|---|
A. Co3+ | (i) $$\sqrt 8 $$ B.M. |
B. Cr3+ | (ii) $$\sqrt {35} $$ B.M. |
C. Fe3+ | (iii) $$\sqrt 3 $$ B.M. |
D. Ni2+ | (iv) $$\sqrt {24} $$ B.M. |
(v) $$\sqrt {15} $$ B.M. |
(At. nos. Ti = 22, Cr = 24, Mn = 25, Ni = 28)
(At. nos. Ce = 58, Sm = 62, Eu = 63, Yb = 70)
(At. nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)
Column $${\rm I}$$ (Substances) |
Column $${\rm I}$$$${\rm I}$$ (Processes) |
|||
---|---|---|---|---|
(A) | Sulphuric acid | (i) | Haber's process | |
(B) | Steel | (ii) | Bessemer's process | |
(C) | Sodium hydroxide | (iii) | Leblanc process | |
(D) | Ammonia | (iv) | Contact process |
(At. nos. Mn = 25, Fe = 26, Co = 27, Ni = 28)
(At. No. Ti = 22, V = 23, Cr = 24, Mn = 25)
(At. no. : Sc = 21, Ti = 22, Ni = 28, Cu = 29, Co = 27)
(Atomic number : Sc = 21, Fe = 26, Ti = 22, Mn = 25)
[At. Nos. Ti = 22, V = 23, Cr = 24, Mn = 25]
(Atomic nos. Y = 39, La = 57, Eu = 63, Lu = 71)
(Atomic no's. Ti = 22, V = 23, Cr = 24, Fe = 26)