1
MCQ (Single Correct Answer)

### AIPMT 2010 Prelims

To get an output Y = 1 in given circuit which of the following input will be correct ?

A
A $\to$ 1,  B $\to$ 0,  C $\to$ 0
B
A $\to$ 1,  B $\to$ 0,  C $\to$ 1
C
A $\to$ 1,  B $\to$ 1,  C $\to$ 0
D
A $\to$ 0,  B $\to$ 1,  C $\to$ 0

## Explanation

The Boolen expression for the given combination is

output Y = (A + B) · C

So it is clear that Y = 1, when A = 1, B = 0 and C = 1
2
MCQ (Single Correct Answer)

### AIPMT 2009

Sodium has body centred packing. Distance between two nearest atoms is 3.7 $\mathop A\limits^ \circ$. The lattice parameter is
A
4.3 $\mathop A\limits^ \circ$
B
3.0 $\mathop A\limits^ \circ$
C
8.6 $\mathop A\limits^ \circ$
D
6.8 $\mathop A\limits^ \circ$

## Explanation

Distance between nearest atoms in body centred cubic lattice (bcc),

d = ${{\sqrt 3 } \over 2}a$

Given d = 3.7 $\mathop A\limits^ \circ$

$\therefore$ $a = {{3.7 \times 2} \over {\sqrt 3 }}$ = 4.3 $\mathop A\limits^ \circ$
3
MCQ (Single Correct Answer)

### AIPMT 2009

A p-n photodiode is fabricated from a semiconductor with a band gap of 2.5 eV. It can detect a signal of wavelength
A
4000 nm
B
6000 nm
C
4000 $\mathop A\limits^ \circ$
D
6000 $\mathop A\limits^ \circ$

## Explanation

$\lambda$max = ${{hc} \over E}$

= ${{6.6 \times {{10}^{ - 34}} \times 3 \times {{10}^8}} \over {2.5 \times 1.6 \times {{10}^{ - 19}}}}$

= 5000 $\mathop A\limits^o$

Now the wavelength detected by photodiode be less than $\lambda$max, hence it can detect a signal of wave length 4000 $\mathop A\limits^o$.
4
MCQ (Single Correct Answer)

### AIPMT 2009

A transistor is operated in common-emitter configuration at VC = 2V such that a change in the base current from 100 $\mu$A to 200 $\mu$A produces a change in the collector current from 5 mA to 10 mA. The current gain is
A
100
B
150
C
50
D
75

## Explanation

Current gain, $\beta$ = ${{\Delta {I_C}} \over {\Delta {I_B}}}$

= ${{\left( {10 - 5} \right) \times {{10}^{ - 3}}} \over {\left( {200 - 100} \right) \times {{10}^{ - 6}}}}$ = 50

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