1
NEET 2016 Phase 2
MCQ (Single Correct Answer)
+4
-1
Change Language
The given circuit has two ideal diodes connected as shown in the figure. The current flowing through the resistance R1 will be

NEET 2016 Phase 2 Physics - Semiconductor Electronics Question 107 English
A
2.5 A
B
10.0 A
C
1.43 A
D
3.13 A
2
NEET 2016 Phase 2
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
For CE transistor amplifier, the aufio signal voltage across the collector resistance of 2 k$$\Omega $$ is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1 k$$\Omega $$, then the input signal voltage is
A
10 mV
B
20 mV
C
30 mV
D
15 mV
3
NEET 2016 Phase 1
MCQ (Single Correct Answer)
+4
-1
Change Language
Consider the junction diode as ideal. The value of current flowing through AB is

NEET 2016 Phase 1 Physics - Semiconductor Electronics Question 103 English
A
10$$-$$1 A
B
10$$-$$3 A
C
0 A
D
10$$-$$2 A
4
NEET 2016 Phase 1
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 $$\Omega $$ is connected in the collector circuit and the voltage frop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192 $$\Omega $$, the voltage gain and the power gain of the amplifier will respectively be
A
4, 4
B
4, 3.69
C
4, 3.84
D
3.69, 3.84
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