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1

### NEET 2016 Phase 2

The given circuit has two ideal diodes connected as shown in the figure. The current flowing through the resistance R1 will be

A
2.5 A
B
10.0 A
C
1.43 A
D
3.13 A

## Explanation

Current will not flow through D1 as it is reversed biased.

Current will flow through resistor R1, diode D2 and resistor R3

Now current i = 10/(2 + 2) = 2.5 A
2

### NEET 2016 Phase 2

For CE transistor amplifier, the aufio signal voltage across the collector resistance of 2 k$$\Omega$$ is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1 k$$\Omega$$, then the input signal voltage is
A
10 mV
B
20 mV
C
30 mV
D
15 mV

## Explanation

Voltage gain, A = $$\beta {{{R_C}} \over {{R_B}}}$$ = $$100 \times {{2000} \over {1000}}$$ = 200

Also, A = $${{{V_0}} \over {{V_i}}}$$

$$\Rightarrow$$ $${V_i} = {{{V_0}} \over A}$$ = $${4 \over {200}}$$ = 20 mA
3

### AIPMT 2015 Cancelled Paper

If in a p-n junction, a square input signal of 10 V is applied, as shown,

then the output across RL will be
A
B
C
D

## Explanation

Here P-N junction diode rectifies half of the ac wave i.e., acts as half wave rectifier.
During + ve half cycle Diode is forward biased output across RL will be

During –ve half cycle Diode is reverse biased output will not obtained.
4

### AIPMT 2015 Cancelled Paper

Which logic gate is represented by the following combination of logic gates ?

A
AND
B
NOR
C
OR
D
NAND

## Explanation

The Boolean expression of this arrangement is

Y = $$\overline {\overline A + \overline B }$$ = $$\overline{\overline A} + \overline{\overline B}$$ = A.B

Thus, the combination represents AND gate.

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NEET

Class 12