1
AIPMT 2012 Mains
MCQ (Single Correct Answer)
+4
-1
Change Language
Standard reduction potentials of the half reactions are given below :
F2(g) + 2e$$-$$ $$ \to $$ 2F$$-$$(aq) ;   Eo = + 2.85 V
Cl2(g) + 2e$$-$$ $$ \to $$ 2Cl$$-$$(aq) ;   Eo = + 1.36 V
Br2(l) + 2e$$-$$ $$ \to $$ 2Br$$-$$(aq) ;   Eo = + 1.06 V
I2(s) + 2e$$-$$ $$ \to $$ 2I$$-$$(aq) ;  Eo = + 0.53 V

The strongest oxidising and reducing agents 23 respectively are
A
F2 and I$$-$$
B
Br2 and Cl$$-$$
C
Cl2 and Br$$-$$
D
Cl2 and I2
2
AIPMT 2012 Prelims
MCQ (Single Correct Answer)
+4
-1
Change Language
Limiting molar conductivity of NH4OH
$$\left[ {} \right.$$i.e.  $$\Lambda _{m\left( {N{H_4}OH} \right)}^0$$$$\left. {} \right]$$ is equal to
A
$$\Lambda _{m\left( {N{H_4}OH} \right)}^0 + \Lambda _{m\left( {NaCl} \right)}^0 - \Lambda _{m\left( {NaOH} \right)}^0$$
B
$$\Lambda _{m\left( {NaOH} \right)}^0 + \Lambda _{m\left( {NaCl} \right)}^0 - \Lambda _{m\left( {N{H_4}Cl} \right)}^0$$
C
$$\Lambda _{m\left( {N{H_4}OH} \right)}^0 + \Lambda _{m\left( {N{H_4}Cl} \right)}^0 - \Lambda _{m\left( {HCl} \right)}^0$$
D
$$\Lambda _{m\left( {N{H_4}Cl} \right)}^0 + \Lambda _{m\left( {NaOH} \right)}^0 - \Lambda _{m\left( {NaCl} \right)}^0$$
3
AIPMT 2011 Mains
MCQ (Single Correct Answer)
+4
-1
A solution contains Fe2+, Fe3+ and I$$-$$ ions. This solution was treated with iodine at 35oC. Eo for Fe3+/Fe2+ is + 0.77 V and Eo for I2/2I$$-$$ = 0.536 V.
The favourable redox reaction is
A
I2 will be reduced to I$$-$$
B
there will be no redox reaction
C
I$$-$$ will be oxidised to I2
D
Fe2+ will be oxidised to Fe3+
4
AIPMT 2011 Prelims
MCQ (Single Correct Answer)
+4
-1
Standard electrode potential of three metals X, Y and Z are $$-$$1.2 V, + 0.5 V and $$-$$ 3.0 V respectively. The reducing power of these metals will be
A
Y > Z > X
B
Y > X > Z
C
Z > X > Y
D
X > Y > Z
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