Consider the change in oxidation state of
bromine corresponding to different emf values
as shown in the given diagram :
Then the species undergoing disproportionation
is :
A
BrO4–
B
BrO3–
C
Br2
D
HBrO
2
NEET 2017
MCQ (Single Correct Answer)
+4
-1
In the electrochemical cell :
$$Zn\left| {ZnS{O_4}\left( {0.01\,M} \right)} \right|$$$$\left| {CuS{O_4}\left( {1.0M} \right)} \right|Cu,$$
the emf of this Daniell cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that of CuSO4 changed to 0.01 M, the emf changes to E2. From the followings, which one is the relationship between E1 and E2? (Given, RT/F = 0.059)
A
E1 < E2
B
E1 > E2
C
E2 = 01E1
D
E1 = E2
3
NEET 2016 Phase 2
MCQ (Single Correct Answer)
+4
-1
The molar conductivity of a 0.5 mol/dm3 solution of AgNO3 with electrolytic conductivity of 5.76 $$ \times $$ 10$$-$$3 S cm$$-$$1 at 298 K is
A
2.88 S cm2/mol
B
11.52 S cm2/mol
C
0.086 S cm2/mol
D
28.8 S cm2/mol
4
NEET 2016 Phase 2
MCQ (Single Correct Answer)
+4
-1
Zinc can be coated on iron to produce galvanized iron but the reverse is not possible. It is because
A
zinc is lighter than iron
B
zinc has lower melting point than iron
C
zinc has lower negative electrode potential than iron
D
zinc has higher negative electrode potential than iron
