1
MCQ (Single Correct Answer)

AIPMT 2007

The efficiency of a fuel cell is given by
A
$$\Delta $$G/$$\Delta $$S
B
$$\Delta $$G/$$\Delta $$H
C
$$\Delta $$S/$$\Delta $$G
D
$$\Delta $$H/$$\Delta $$G

Explanation

Efficiency of a fuel cell ($$\phi $$) = $${{\Delta G} \over {\Delta H}} \times 100$$

Generally, fuel cells are expected to have an efficiency of 100 percent.
2
MCQ (Single Correct Answer)

AIPMT 2007

The equilibrium constant of the reaction:
Cu(s) + 2Ag+(aq) $$ \to $$ Cu2+(aq) + 2Ag(s);
Eo = 0.46 V at 298 K is
A
2.0 $$ \times $$ 1010
B
4.0 $$ \times $$ 1010
C
4.0 $$ \times $$ 1015
D
2.4 $$ \times $$ 1010

Explanation

RT ln K = nFE°

ln K = $${{nFE^\circ } \over {RT}}$$

= $${{2 \times 0.46} \over {0.0591}}$$

$$ \Rightarrow $$ K = 4 $$ \times $$ 1015
3
MCQ (Single Correct Answer)

AIPMT 2006

A hypothetical electrochemical cell is shown below.

$$A\left| {{A^ + }\left( {xM} \right)} \right|\left| {{B^ + }\left( {yM} \right)} \right|B$$

The emf measured is + 0.20 V. The cell reaction is
A
A + B+ $$ \to $$ A+ + B
B
A+ + B $$ \to $$ A + B+
C
A+ + e$$-$$ $$ \to $$ A;  B+ + e$$-$$ $$ \to $$ B
D
the cell reaction cannot be predicted.

Explanation

From the given expression:

At anode : A $$ \to $$ A+ + e

At cathode : B+ + e $$ \to $$ B

Overall reaction is : A + B+ $$ \to $$ A+ + B
4
MCQ (Single Correct Answer)

AIPMT 2006

EoFe2+/Fe = $$-$$ 0.441 V and EoFe3+/Fe2+ = 0.771 V, the standard EMF of the reaction Fe + 2Fe3+ $$ \to $$ 3Fe2+ will be
A
0.111 V
B
0.330 V
C
1.653 V
D
1.212 V

Explanation

At anode : Fe $$ \to $$ Fe2+ + 2e-; Eo = -0.441 V

At cathode : Fe3+ + e $$ \to $$ Fe2+; Eo = 0.771 V

Fe + 2Fe3+ $$ \to $$ 3Fe2+; Eo = ?

To get the above equation, (ii) × 2 – (i)

2Fe3+ + 2e $$ \to $$ 2Fe2+; Eo = 0.771 V

Fe $$ \to $$ Fe2+ + 2e-; Eo = - 0.441 V
------------------------------------------------
Fe + 2Fe3+ $$ \to $$ 3Fe2+

Eo = 0.771 + 0.441 = 1.212 V

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