1
AIPMT 2012 Mains
MCQ (Single Correct Answer)
+4
-1
Change Language
Molar conductivities $$\left( {\Lambda _m^o} \right)$$ at infinite dilution of NaCl, Hcl and CH3COONa are 126.4, 425.9 and 91.0 S cm2 mol$$-$$1 respectively. $$\left( {\Lambda _m^o} \right)$$ for CH3COOH will be
A
425.5 S cm2 mol$$-$$1
B
180.5 S cm2 mol$$-$$1
C
290.8 S cm2 mol$$-$$1
D
390.5 S cm2 mol$$-$$1
2
AIPMT 2012 Prelims
MCQ (Single Correct Answer)
+4
-1
Change Language
Limiting molar conductivity of NH4OH
$$\left[ {} \right.$$i.e.  $$\Lambda _{m\left( {N{H_4}OH} \right)}^0$$$$\left. {} \right]$$ is equal to
A
$$\Lambda _{m\left( {N{H_4}OH} \right)}^0 + \Lambda _{m\left( {NaCl} \right)}^0 - \Lambda _{m\left( {NaOH} \right)}^0$$
B
$$\Lambda _{m\left( {NaOH} \right)}^0 + \Lambda _{m\left( {NaCl} \right)}^0 - \Lambda _{m\left( {N{H_4}Cl} \right)}^0$$
C
$$\Lambda _{m\left( {N{H_4}OH} \right)}^0 + \Lambda _{m\left( {N{H_4}Cl} \right)}^0 - \Lambda _{m\left( {HCl} \right)}^0$$
D
$$\Lambda _{m\left( {N{H_4}Cl} \right)}^0 + \Lambda _{m\left( {NaOH} \right)}^0 - \Lambda _{m\left( {NaCl} \right)}^0$$
3
AIPMT 2011 Mains
MCQ (Single Correct Answer)
+4
-1
A solution contains Fe2+, Fe3+ and I$$-$$ ions. This solution was treated with iodine at 35oC. Eo for Fe3+/Fe2+ is + 0.77 V and Eo for I2/2I$$-$$ = 0.536 V.
The favourable redox reaction is
A
I2 will be reduced to I$$-$$
B
there will be no redox reaction
C
I$$-$$ will be oxidised to I2
D
Fe2+ will be oxidised to Fe3+
4
AIPMT 2011 Prelims
MCQ (Single Correct Answer)
+4
-1
Standard electrode potential for Sn4+/Sn2+ couple is + 0.15 V and that for the Cr3+/Cr couple is $$-$$ 0.74 V. These two couples in their standard state are connected to make a cell. The cell potential will be
A
+ 1.19 V
B
+ 0.89 V
C
+ 0.18 V
D
+ 1.83 V

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