1
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
Two boys are standing at points A and B on ground where distance AB = a. The boy at point B starts running perpendicular to line AB with velocity '$V_1$'. The boy at point A starts running simultaneously with velocity 'V' and catches the other boy in time 't'. The value of 't' is
A
$\left[\dfrac{a^2}{(V^2 - V_1^2)}\right]^{\frac{1}{2}}$
B
$\left[\dfrac{a^2}{(V_1^2 - V^2)}\right]^{\frac{1}{2}}$
C
$\left[\dfrac{a^2}{(V^2 - V_1^2)}\right]$
D
$\left[\dfrac{a^2}{(V_1^2 - V^2)}\right]$
2
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A batsman hits a ball with a velocity 'v', making an angle of $60^\circ$ with the vertical. After some time direction of velocity is making an angle of $60^\circ$ with the horizontal. The speed of the ball at this instant is
$\left[\cos(60^\circ) = \dfrac{1}{2}, \cos(30^\circ) = \dfrac{\sqrt{3}}{2}\right]$
A
$\dfrac{\sqrt{3}}{2}v$
B
$\sqrt{3}v$
C
$\dfrac{v}{2}$
D
$V$
3
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A stone falls from the top of a tower of height $100$ m and at the same time another stone is projected vertically upwards from the ground with a velocity $25$ m/s. The two stones meet after
A
$2$ s
B
$5$ s
C
$4$ s
D
$3$ s
4
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A car moving at a speed ' V ' is stopped in a certain distance when the breaks produce a deceleration ' $a$ '. If the speed of the car is ' $n v$ ', what must be the deceleration of the car to stop it in the same distance and in the same time?

A

$\sqrt{n} \cdot a$

B

$n \cdot a$

C

$n^2 \cdot a$

D

$\mathrm{n}^3 \cdot \mathrm{a}$

MHT CET Subjects

Browse all chapters by subject