1
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
Two balls A and B are projected at an angle of $45^\circ$ and $60^\circ$ respectively, so that the maximum heights reached are same for both. The ratio of initial velocity of projection of ball A to that for ball B is
$(\sin 30^\circ = \cos 60^\circ = \dfrac{1}{2},\ \sin 45^\circ = \cos 45^\circ = \dfrac{1}{\sqrt{2}},\ \sin 60^\circ = \cos 30^\circ = \dfrac{\sqrt{3}}{2})$
A
$2 : \sqrt{3}$
B
$\sqrt{3} : 2$
C
$\sqrt{2} : \sqrt{3}$
D
$\sqrt{3} : \sqrt{2}$
2
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
Two objects are projected with same velocity 'u' at different angles $\alpha$ and $\beta$ with the horizontal. If $\alpha + \beta = 90^\circ$, the ratio of horizontal range of the first object to the second object will be $[\sin(\pi - \theta) = \sin\theta]$
A
$4 : 1$
B
$2 : 1$
C
$1 : 1$
D
$1 : 2$
3
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A ball is released from height 'h' which makes perfectly elastic collision with ground. The frequency of periodic vibratory motion is (g=acceleration due to gravity)
A
$\dfrac{1}{2}\sqrt{\dfrac{g}{2h}}$
B
$\dfrac{1}{2}\sqrt{\dfrac{2h}{g}}$
C
$\dfrac{1}{2\pi}\sqrt{\dfrac{g}{2h}}$
D
$\dfrac{1}{2\pi}\sqrt{\dfrac{2h}{g}}$
4
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
Two boys are standing at points A and B on ground where distance AB = a. The boy at point B starts running perpendicular to line AB with velocity '$V_1$'. The boy at point A starts running simultaneously with velocity 'V' and catches the other boy in time 't'. The value of 't' is
A
$\left[\dfrac{a^2}{(V^2 - V_1^2)}\right]^{\frac{1}{2}}$
B
$\left[\dfrac{a^2}{(V_1^2 - V^2)}\right]^{\frac{1}{2}}$
C
$\left[\dfrac{a^2}{(V^2 - V_1^2)}\right]$
D
$\left[\dfrac{a^2}{(V_1^2 - V^2)}\right]$

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