1
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The acceleration of a moving body can be found from

A
area under velocity - time graph.
B
area under distance - time graph.
C
slope of the velocity - time graph.
D
slope of the distance - time graph.
2
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The position '$$x$$' of a particle varies with a time as $$x=a t^2-b t^3$$ where '$$a$$' and '$$b$$' are constants. The acceleration of the particle will be zero at

A
$$\frac{2 \mathrm{a}}{3 \mathrm{~b}}$$
B
$$\frac{\mathrm{a}}{\mathrm{b}}$$
C
$$\frac{a}{3 b}$$
D
zero
3
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two bodies $$A$$ and $$B$$ start from the same point at the same instant and move along a straight line. body $$A$$ moves with uniform acceleration $$a$$ and body $$B$$ moves with uniform velocity $$v$$. They meet after time $$t$$. The value of $$t$$ is

A
$$\frac{2 v}{a}$$
B
$$\frac{a}{2 v}$$
C
$$\frac{v}{2 a}$$
D
$$\sqrt{\frac{v}{a}}$$
4
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A small steel ball is dropped from a height of $$1.5 \mathrm{~m}$$ into a glycerine jar. The ball reaches the bottom of the jar $$1.5 \mathrm{~s}$$ after it was dropped. If the retardation is $$2.66 \mathrm{~m} / \mathrm{s}^2$$, the height of the glycerine in the jar is about (acceleration due to gravity $$g=9.8 \mathrm{~m} / \mathrm{s}^2$$ )

A
7.0 m
B
7.5 m
C
5.5 m
D
3.2 m
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