1
MHT CET 2025 21st April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A body starts from rest and moves with a uniform acceleration. The ratio of the distance covered by the body in the $n^{\text {th }}$ second of its motion to the total distance travelled in n second is

A
$\frac{2}{n^2}-\frac{1}{n}$
B
$\frac{2}{n}-\frac{1}{n^2}$
C
$\frac{1}{\mathrm{n}}-\frac{1}{\mathrm{n}^2}$
D
$\frac{2}{\mathrm{n}^2}+\frac{1}{\mathrm{n}}$
2
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+1
-0

The velocity time graph of a body moving in a straight line is shown in figure. The ratio of displacement to distance travelled by the body in time 0 to 8 s is

MHT CET 2025 21st April Morning Shift Physics - Motion Question 2 English
A
$8: 5$
B
$3: 5$
C
$5: 9$
D
$7: 4$
3
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two bodies A and B move in same straight line starting from same position. Body moves with constant velocity ' u ' and body B moves with constant acceleration ' $a$ '. When their velocities become equal, the distance between them is

A
$\frac{\mathrm{u}}{2 \mathrm{a}}$
B
$\frac{\mathrm{u}^2}{4 \mathrm{a}}$
C
$\frac{\mathrm{u}^2}{\mathrm{a}}$
D
$\frac{\mathrm{u}^2}{2 \mathrm{a}}$
4
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A force acting on a body of mass 5 Kg is $(4 \hat{i}-2 \hat{j}+3 \hat{k}) \mathrm{N}$. If the body is initially at rest then the magnitude of its velocity at the end of 10 second in $\mathrm{m} / \mathrm{s}$ will be

A
$3 \sqrt{35}$
B
$2 \sqrt{29}$
C
$\sqrt{19}$
D
$3 \sqrt{23}$
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