1
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
The angular momentum of the electron in the third Bohr orbit of a hydrogen atom is '$l$' so its angular momentum in the fourth Bohr orbit is
A
$4l$
B
$\left(\dfrac{5}{4}\right)l$
C
$\left(\dfrac{4}{3}\right)l$
D
$\left(\dfrac{3}{2}\right)l$
2
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
In Bohr's atomic model, the energy of the electron is 'E' in the second orbit of hydrogen atom. So the energy of the electron in the third orbit of helium atom $(Z = 2)$ will be
A
$\dfrac{16\,E}{3}$
B
$\dfrac{16\,E}{9}$
C
$\dfrac{4\,E}{3}$
D
$\dfrac{4\,E}{9}$
3
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
The activity of a radioactive sample is measured as $N_0$ counts per minute at time $t = 0$ and $\dfrac{N_0}{e}$ counts per minute at time $t = 3$ minute. The time (in minute) in which the activity reduces to half the value, is
A
$\dfrac{1}{3}\log_e 2$
B
$3\log_e 2$
C
$3\log_{10} 2$
D
$\dfrac{3}{\log_e 2}$
4
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
For wavelength of visible radiation of Hydrogen spectrum, Balmer gave an equation as $\lambda = \dfrac{xm^2}{m^2-4}$, where m is the integer value. The value of x in terms of Rydberg's constant R is
A
$\dfrac{R}{4}$
B
$\dfrac{4}{R}$
C
$2R$
D
$4R$

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