MHT CET 2024 11th May Morning Shift | Fluid Mechanics Question 16 | Physics

Water rises in a capillary tube of radius ' $r$ ' up to height ' $h$ '. The mass of water in capillary is ' $m$ '. The mass of water that will rise in capillary of radius $\mathrm{r} / 3$ will be

$\frac{\mathrm{m}}{3}$

$\frac{m}{6}$

$\frac{\mathrm{m}}{9}$

MHT CET 2024 11th May Morning Shift

MCQ (Single Correct Answer)

-0

The work done in blowing a soap bubble of radius $R$ is $W_1$ at room temperature. Now the soap solution is heated. From the heated solution another soap bubble of radius 2 R is blown and the work done is $\mathrm{W}_2$. Then

$\mathrm{W}_2=0$

$\mathrm{W}_2=4 \mathrm{~W}_1$

$\mathrm{W}_2<4 \mathrm{~W}_1$

$\mathrm{W}_2=\mathrm{W}_1$

MHT CET 2024 10th May Evening Shift

MCQ (Single Correct Answer)

-0

Two soap bubbles having radii ' $r_1$ ' and ' $r_2$ ' has inside pressure ' $P_1$ ' and ' $\mathrm{P}_2$ ' respectively. If $\mathrm{P}_0$ is external pressure then ratio of their volume is

$\frac{\left(\mathrm{P}_1-\mathrm{P}_0\right)}{\left(\mathrm{P}_2-\mathrm{P}_0\right)}$

$\frac{\left(\mathrm{P}_2-\mathrm{P}_0\right)}{\left(\mathrm{P}_1-\mathrm{P}_0\right)}$

$\frac{\left(P_2-P_0\right)^3}{\left(P_1-P_0\right)^3}$

$\frac{\left(\mathrm{P}_1-\mathrm{P}_0\right)^3}{\left(\mathrm{P}_2-\mathrm{P}_0\right)^3}$

MHT CET 2024 10th May Evening Shift

MCQ (Single Correct Answer)

-0

Two metal spheres are falling through a liquid of density $2.5 \times 10^3 \mathrm{~kg} / \mathrm{m}^3$ with the same uniform speed. The density of material of first sphere and second sphere is $11.5 \times 10^3 \mathrm{~kg} / \mathrm{m}^3$ and $8.5 \times 10^3 \mathrm{~kg} / \mathrm{m}^3$ respectively. The ratio of the radius of first sphere to that of second sphere is

$\frac{2}{3}$

$\sqrt{\frac{2}{3}}$

$\frac{3}{2}$

$\sqrt{\frac{3}{2}}$

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