MHT CET 2024 10th May Morning Shift | Atoms and Nuclei Question 16 | Physics

Using Bohr's model, the orbital period of electron in hydrogen atom in $\mathrm{n}^{\text {th }}$ orbit is ( $\mathrm{m}=$ mass of electron, $\mathrm{h}=$ Planck's constant, $\mathrm{e}=$ electronic charge, $\varepsilon_0=$ permittivity of free space)

$\frac{2 \varepsilon_0^2 n^2 h^2}{m e^4}$

$\frac{4 \varepsilon_0^2 \mathrm{n}^2 \mathrm{~h}^2}{\mathrm{me}^2}$

$\frac{4 \varepsilon_0^2 \mathrm{n}^3 \mathrm{~h}^3}{\mathrm{me}^4}$

$\frac{4 \varepsilon_0 \mathrm{n}^2 \mathrm{~h}^2}{\pi \mathrm{me}^2}$

MHT CET 2024 9th May Evening Shift

MCQ (Single Correct Answer)

-0

The spectral series observed for hydrogen atom found in visible region is

Lyman

Balmer

Paschen

Brackett

MHT CET 2024 9th May Evening Shift

MCQ (Single Correct Answer)

-0

In hydrogen atom, if $\mathrm{V}_{\mathrm{n}}$ and $\mathrm{V}_{\mathrm{p}}$ are orbital velocities in $\mathrm{n}^{\text {th }}$ and $\mathrm{p}^{\text {th }}$ orbit respectively, then the ratio $\mathrm{V}_{\mathrm{p}}: \mathrm{V}_{\mathrm{n}}$ is

$\mathrm{p}: \mathrm{n}$

$\mathrm{n}: \mathrm{p}$

$\mathrm{p}^2: \mathrm{n}^2$

$\mathrm{n}^2: \mathrm{p}^2$

MHT CET 2024 9th May Morning Shift

MCQ (Single Correct Answer)

-0

When a hydrogen atom is raised from the ground state to the excited state

potential energy increases and K.E. decreases.

potential energy decreases and K.E. increases.

both K.E. and potential energy will increase.

both K.E. and potential energy decreases.

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