1
MHT CET 2021 24th September Morning Shift
+1
-0

Two long conductors, separated by a distance '$$\mathrm{d}$$' carry currents '$$\mathrm{I}_1$$' and '$$\mathrm{I}_2$$' in the same directions. They exert a force '$$\mathrm{F}$$' on each other. Now the current in one of them is increased to two times and its direction is reversed. The distance is also increased to '$$3 \mathrm{~d}$$'. The new value of the force between them is

A
$$-2 \mathrm{~F}$$
B
$$-\mathrm{F}$$
C
$$-\frac{2 \mathrm{~F}}{3}$$
D
$$\frac{\mathrm{F}}{3}$$
2
MHT CET 2021 23rd September Evening Shift
+1
-0

An electron in a circular orbit of radius $$0.05 \mathrm{~nm}$$ performs $$10^{14}$$ revolutions/second. What is the magnetic moment due to the rotation of electron? $$(\mathrm{e}=1.6 \times 10^{-19} \mathrm{C})$$

A
$$3.21 \times 10^{-23}$$
B
$$2.16 \times 10^{-23}$$
C
$$3.21 \times 10^{-22}$$
D
$$1.26 \times 10^{-28}$$
3
MHT CET 2021 23rd September Evening Shift
+1
-0

A long solenoid carrying current $$\mathrm{I}_1$$ produces magnetic field $$\mathrm{B}_1$$ along its axis. If the current is reduced to $$20 \%$$ and number of turns per $$\mathrm{cm}$$ are increased five times then new magnetic field B$$_2$$ is equal to

A
$$\mathrm{B}_1$$
B
$$\frac{B_1}{5}$$
C
$$5 \mathrm{B}_1$$
D
$$0.25 \mathrm{B}_1$$
4
MHT CET 2021 23rd September Evening Shift
+1
-0

A straight wire of diameter $$0.4 \mathrm{~mm}$$ carrying a current of $$2 \mathrm{~A}$$ is replaced by another wire of 0.8 $$\mathrm{mm}$$ diameter carrying the same current. The magnetic field at distance $$(\mathrm{R})$$ from both the wires is 'B$$_1$$' and 'B$$_2$$' respectively. The relation between B$$_1$$ and B$$_2$$ is

A
$$B_1=\frac{B_2}{2}$$
B
$$B_1=B_2$$
C
$$\mathrm{B}_1=2 \mathrm{~B}_2$$
D
$$\mathrm{B}_1=\frac{\mathrm{B}_2}{3}$$
EXAM MAP
Medical
NEET