MHT CET 2024 11th May Morning Shift | Moving Charges and Magnetism Question 15 | Physics

The magnetic flux near the axis and inside the air core solenoid of length 80 cm carrying current ' I ' is $1.57 \times 10^{-6} \mathrm{~Wb}$. Its magnetic moment will be [cross-sectional area of a solenoid is very small as compared to its length, $\mu_0=4 \pi \times 10^{-7}$ SI unit $](\pi=3.14)$

$0.25 \mathrm{~Am}^2$

$0.50 \mathrm{~Am}^2$

$1 \mathrm{~Am}^2$

$1.2 \mathrm{~Am}^2$

MHT CET 2024 11th May Morning Shift

MCQ (Single Correct Answer)

-0

Two long straight parallel wires are separated by a distance '2d'. Each wire carries a current 'I' in the same direction. The magnetic field at a point 'P' midway between them is

$\frac{2 \mu_0 I}{r}$

zero

$\frac{\mu_0 I}{4 r}$

$\frac{\mu_0 I}{2 r}$

MHT CET 2024 10th May Evening Shift

MCQ (Single Correct Answer)

-0

The magnitude of magnetic field at point 'O' in the following figure will be

MHT CET 2024 10th May Evening Shift Physics - Moving Charges and Magnetism Question 15 English

$\frac{\mu_0}{4 \pi} \frac{\mathrm{I}}{\mathrm{r}}\left(\frac{2}{\pi}+2\right)$

$\frac{\mu_0}{4 \pi} \frac{\mathrm{I}}{\mathrm{r}}\left(\frac{2}{\pi}-2\right)$

$\frac{\mu_0}{4 \pi} \frac{\mathrm{I}}{\mathrm{r}}\left(2+\frac{\pi}{2}\right)$

$\frac{\mu_0}{4 \pi} \frac{\mathrm{I}}{\mathrm{r}}\left(2-\frac{\pi}{2}\right)$

MHT CET 2024 10th May Evening Shift

MCQ (Single Correct Answer)

-0

A coil of ' $n$ ' turns and radius ' $R$ ' carries a current 'I'. It is unwound and rewound to make a new coil of radius $\frac{R}{3}$ and the same current is passed through it. The ratio of the magnetic moment of the new coil to that of the original coil is

$\frac{1}{3}$

$\frac{1}{2}$

PREVIOUS NEXT

MHT CET Subjects