MHT CET 2021 20th September Morning Shift | Fluid Mechanics Question 143 | Physics

The force required to take away a flat circular plate of radius $$2 \mathrm{~cm}$$ from the surface of water is $$\left[\right.$$Surface tension of water $$\left.=70 \times 10^{-3} \mathrm{Nm}^{-1}, \pi=\frac{22}{7}\right]$$

$$4.4 \times 10^{-4} \mathrm{~N}$$

$$8.8 \times 10^{-3} \mathrm{~N}$$

$$6.6 \times 10^{-4} \mathrm{~N}$$

$$11 \times 10^{-3} \mathrm{~N}$$

MHT CET 2020 19th October Evening Shift

MCQ (Single Correct Answer)

-0

Two spherical rain drops reach the surface of the earth with terminal velocities having ratio $16: 9$. The ratio of their surface area is

$4: 3$

$64: 27$

$16: 9$

$9: 16$

MHT CET 2020 19th October Evening Shift

MCQ (Single Correct Answer)

-0

Water rises upto a height $h$ in a capillary tube on the surface of the earth. The value of $h$ will increase, if the experimental setup is kept in [ $g=$ acceleration due to gravity]

a lift going upward with a certain acceleration

accelerating train

a satellite rotating close to earth

a lift going down with acceleration $a< g$

MHT CET 2020 19th October Evening Shift

MCQ (Single Correct Answer)

-0

If the surface tension of a soap solution is $3 \times 10^{-2} \mathrm{~N} / \mathrm{m}$ then the work done in forming a soap film of $20 \mathrm{~cm} \times 5 \mathrm{~cm}$ will be

$6 \times 10^{-2} \mathrm{~J}$

6 J

$6 \times 10^{-4} \mathrm{~J}$

$6 \times 10^{-3} \mathrm{~J}$

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