MHT CET 2022 11th August Evening Shift | Capacitor Question 24 | Physics

A parallel plate capacitor is charged and then disconnected from the charging battery. If the plates are now moved further apart by pulling them by means of insulating handles, then

the capacitance of the capacitor increases

the charge on the capacitor decreases

the voltage across the capacitor increases

the energy stored in the capacitor decreases

MHT CET 2022 11th August Evening Shift

MCQ (Single Correct Answer)

-0

The force between the plates of a parallel plate capacitor of capacitance '$$\mathrm{C}$$' and distance of separation of the plates '$$\mathrm{d}$$' with a potential difference '$$\mathrm{V}$$' between the plates is

$$\frac{\mathrm{V}^2 \mathrm{~d}}{\mathrm{C}}$$

$$\frac{\mathrm{C}^2 \mathrm{~V}^2}{\mathrm{~d}^2}$$

$$\frac{\mathrm{CV}^2}{2 \mathrm{~d}}$$

$$\frac{\mathrm{C}^2 \mathrm{~V}^2}{2 \mathrm{~d}^2}$$

MHT CET 2021 22th September Evening Shift

MCQ (Single Correct Answer)

-0

In parallel plate capacitor, electric field between the plates is '$$E$$'. If the charge on the plates is '$$Q$$' then the force on each plate is

$$\frac{\mathrm{QE}^2}{2}$$

$$\mathrm{QE}^2$$

$$\frac{\mathrm{QE}}{2}$$

MHT CET 2021 21th September Evening Shift

MCQ (Single Correct Answer)

-0

Two identical parallel plate air capacitors are connected in series to a battery of emf '$$\mathrm{V}$$'. If one of the capacitor is inserted in liquid of dielectric constant '$$\mathrm{K}$$' then, potential difference of the other capacitor will become

$$\frac{\mathrm{K}-1}{\mathrm{KV}}$$

$$\frac{\mathrm{K}+1}{\mathrm{KV}}$$

$$\left(\frac{\mathrm{KV}}{\mathrm{K}+1}\right)$$

$$\frac{\mathrm{KV}}{\mathrm{K}-1}$$

PREVIOUS NEXT

MHT CET Subjects