1
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

For an ideal gas the density of the gas is $$\rho_0$$ when temperature and pressure of the gas are $$T_0$$ and $$P_0$$ respectively. When the temperature of the gas is $$2 \mathrm{~T}_0$$, its pressure will be $$3 \mathrm{P}_0$$. The new density will be

A
$$\frac{3}{2} \rho_0$$
B
$$\frac{4}{3} \rho_0$$
C
$$\frac{3}{4} \rho_0$$
D
$$\frac{2}{3} \rho_0$$
2
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The temperature gradient in a rod of length $$75 \mathrm{~cm}$$ is $$40^{\circ} \mathrm{C} / \mathrm{m}$$. If the temperature of cooler end of the rod is $$10^{\circ} \mathrm{C}$$, then the temperature of hotter end is

A
$$50^{\circ} \mathrm{C}$$
B
$$40^{\circ} \mathrm{C}$$
C
$$35^{\circ} \mathrm{C}$$
D
$$25^{\circ} \mathrm{C}$$
3
MHT CET 2023 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A black body radiates maximum energy at wavelength '$$\lambda$$' and its emissive power is '$$E$$'. Now due to a change in temperature of that body, it radiates maximum energy at wavelength $$\frac{\lambda}{3}$$. At that temperature emissive power is

A
$$16: 1$$
B
$$256: 1$$
C
$$81: 1$$
D
$$128: 1$$
4
MHT CET 2023 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

For polyatomic gases, the ratio of molar specific heat at constant pressure to constant volume is ( $$\mathrm{f}=$$ degrees of freedom)

A
$$\frac{2+\mathrm{f}}{3+\mathrm{f}}$$
B
$$\frac{3+\mathrm{f}}{2+\mathrm{f}}$$
C
$$\frac{3+\mathrm{f}}{4+\mathrm{f}}$$
D
$$\frac{4+\mathrm{f}}{3+\mathrm{f}}$$
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