1
MHT CET 2021 22th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

Assuming the atom is in the ground state, the expression for the magnetic field at a point nucleus in hydrogen atom due to circular motion of electron is [$$\mu_0=$$ permeability of free space, $$\mathrm{m}=$$ mass of electron, $$\epsilon_0=$$ permittivity of free space, $$\mathrm{h}=$$ Planck's constant ]

A
$$\frac{\mu_0 \mathrm{e}^7 \pi \mathrm{m}^2}{8 \in_0^3 \mathrm{~h}^5}$$
B
$$\frac{\mu_0 \mathrm{e}^5 \pi \mathrm{m}^3}{8 \epsilon_0^3 \mathrm{~h}^5}$$
C
$$\frac{\mu_0 \mathrm{e}^5 \pi^2 \mathrm{~m}^2}{8 \epsilon_0^2 \mathrm{~h}^4}$$
D
$$\frac{\mu_0 \mathrm{e}^7 \pi^2 \mathrm{~m}^2}{8 \epsilon_0^3 \mathrm{~h}^5}$$
2
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

A, B and C are three parallel conductors of equal lengths carrying currents $$\mathrm{I}, \mathrm{I}$$ and $$2 \mathrm{I}$$ respectively. Distance between A and B is '$$x$$' and that between B and C is also '$$x$$'. $$F_1$$ is the force exerted by conductor $$\mathrm{B}$$ on $$\mathrm{A}$$. $$\mathrm{F}_2$$ is the force exerted by conductor $$\mathrm{C}$$ on $$\mathrm{A}$$. Current $$\mathrm{I}$$ in $$\mathrm{A}$$ and $$\mathrm{I}$$ in $$\mathrm{B}$$ are in same direction and current $$2 \mathrm{I}$$ in $$\mathrm{C}$$ is in opposite direction. Then

A
$$\mathrm{F}_1=\mathrm{F}_2$$
B
$$\mathrm{F}_2=2 \mathrm{R}_1$$
C
$$F_1=2 R_2$$
D
$$F_1=-F_2$$
3
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Magnetic moment of revolving electron of charge (e) and mass (m) in terms of angular momentum (L) of electron is :

A
$$\frac{e L}{8 m}$$
B
$$\frac{\mathrm{eL}}{4 \mathrm{~m}}$$
C
$$\frac{\mathrm{eL}}{2 \mathrm{~m}}$$
D
$$\frac{\mathrm{eL}}{\mathrm{m}}$$
4
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The magnetic flux near the axis and inside the air core solenoid of length $$60 \mathrm{~cm}$$ carrying current '$$\mathrm{I}$$' is $$1.57 \times 10^{-6} \mathrm{~Wb}$$. Its magnetic moment will be $$\left[\mu_0=4 \pi \times 10^{-7}\right.$$, SI unit and crosssectional area is very small as compared to length of solenoid.]

A
$$1 ~\mathrm{Am}^2$$
B
$$0.25 ~\mathrm{Am}^2$$
C
$$0.5 ~\mathrm{Am}^2$$
D
$$0.75 ~\mathrm{Am}^2$$
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