MHT CET 2020 16th October Evening Shift | Fluid Mechanics Question 76 | Physics

A square frame of each side $$L$$ is dipped in a soap solution and taken out. The force acting on the film formed is ($$T=$$ surface tension of soap solution)

$$8 T L$$

$$2 T L$$

$$R=\left(R_1^3+R_2^3\right)^{1 / 3}$$

12 TL

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

Water rises in a capillary tube of radius $$r$$ upto a height $$h$$. The mass of water in a capillary is $$m$$. The mass of water that will rise in a capillary of radius $$\frac{r}{4}$$ will be

$$4 m$$

$$\frac{m}{4}$$

$$m$$

$$\frac{4}{m}$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

A small metal sphere of mass $$M$$ and density $$d_1$$ when dropped in a jar filled with liquid moves with terminal velocity after sometime. The viscous force acting on the sphere is ($$d_2=$$ density of liquid and $$g=$$ gravitational acceleration)

$$M g\left(\frac{d_1}{d_2}\right)$$

$$M g\left(1-\frac{d_2}{d_1}\right)$$

$$M g\left(\frac{d_2}{d_1}\right)$$

$$M g\left(1-\frac{d_1}{d_2}\right)$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

Two small drops of mercury each of radius $$r$$ coalesce to form a large single drop. The ratio of the total surface energies before and after the change is

$$\sqrt{2}: 1$$

$$2^{\frac{1}{3}}: 1$$

$$2: 1$$

$$2^{\frac{2}{3}}: 1$$

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