1
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A single turn current loop in the shape of a right angle triangle with side $$5 \mathrm{~cm}, 12 \mathrm{~cm}, 13 \mathrm{~cm}$$ is carrying a current of $$2 \mathrm{~A}$$. The loop is in a uniform magnetic field of magnitude $$0.75 \mathrm{~T}$$ whose direction is parallel to the current in the $$13 \mathrm{~cm}$$ side of the loop. The magnitude of the magnetic force on the $$5 \mathrm{~cm}$$ side will be $$\frac{\mathrm{x}}{130} \mathrm{~N}$$. The value of '$$x$$' is

A
4
B
9
C
12
D
15
2
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two long conductors separated by a distance '$$\mathrm{d}$$' carry currents $$I_1$$ and $$I_2$$ in the same direction. They exert a force '$$F$$' on each other. Now the current in one of them is increased to two times and its direction is reversed. The distance between them is also increased to $$3 \mathrm{~d}$$. The new value of force between them is

A
$$-2 \mathrm{~F}$$
B
$$\frac{\mathrm{F}}{3}$$
C
$$\frac{-2 \mathrm{~F}}{3}$$
D
$$\frac{-\mathrm{F}}{3}$$
3
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A circular arc of radius '$$r$$' carrying current '$$\mathrm{I}$$' subtends an angle $$\frac{\pi}{16}$$ at its centre. The radius of a metal wire is uniform. The magnetic induction at the centre of circular arc is $$\left[\mu_0=\right.$$ permeability of free space]

A
$$\frac{\mu_0 \mathrm{I}}{32 \mathrm{r}}$$
B
$$\frac{\mu_0 \mathrm{I}}{16 \mathrm{r}}$$
C
$$\frac{\mu_0 \mathrm{I}}{64 \mathrm{r}}$$
D
$$\frac{\mu_0 \mathrm{I}}{8 \mathrm{r}}$$
4
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A cylindrical magnetic rod has length $$5 \mathrm{~cm}$$ and diameter $$1 \mathrm{~cm}$$. It has uniform magnetization $$5.3 \times 10^3 \mathrm{~A} / \mathrm{m}^3$$. Its net magnetic dipole moment is nearly

A
$$1 \times 10^{-2} \mathrm{~J} / \mathrm{T}$$
B
$$0.5 \times 10^{-2} \mathrm{~J} / \mathrm{T}$$
C
$$2.5 \times 10^{-2} \mathrm{~J} / \mathrm{T}$$
D
$$2 \times 10^{-2} \mathrm{~J} / \mathrm{T}$$
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