1
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+2
-0

A random variable $X$ has the following probability distribution

$\mathrm{X=}x_i$: 1 2 3 4
$\mathrm{P(X=}x_i)$ : 0.2 0.4 0.3 0.1

The mean and variance of X are respectively

A
2.3 and 6.1
B
2.3 and 0.1
C
2.3 and 0.81
D
2.3 and 0.9
2
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The mean of 100 observations is 50 and their standard deviation is 5 , then the sum of all squares of all the observations is

A
252500
B
250500
C
250000
D
255000
3
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If both mean and variance of 50 observations $$x_1, x_2, \ldots, x_{50}$$ are equal to 16 and 256 respectively, then mean of $$\left(x_1-5\right)^2,\left(x_2-5\right)^2, \ldots \ldots,\left(x_{50}-5\right)^2$$ is

A
357
B
367
C
377
D
387
4
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The variance of 20 observations is 5. If each observation is multiplied by 2, then variance of resulting observations is

A
5
B
10
C
4
D
20
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