MHT CET 2024 3rd May Morning Shift | Fluid Mechanics Question 41 | Physics

A metal ball of radius $9 \times 10^{-4} \mathrm{~m}$ and density $10^4 \mathrm{~kg} / \mathrm{m}^3$ falls freely under gravity through a distance ' h ' and enters a tank of water. Considering that the metal ball has constant velocity, the value of $h$ is [coefficient of viscosity of water $=8.1 \times 10^{-4} \mathrm{pa}-\mathrm{s}, \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ density of water $\left.=10^3 \mathrm{~kg} / \mathrm{m}^3\right]$

20 m

18 m

15 m

12 m

MHT CET 2024 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

Liquid drops are falling slowly one by one from vertical glass tube. The relation between the weight of a drop ' $w$ ', the surface tension ' $T$ ' and the radius ' $r$ ' of the bore of the tube is (Angle of contact is zero)

$\mathrm{W}=\pi \mathrm{r}^2 \mathrm{~T}$

$\mathrm{W}=2 \pi^2 \mathrm{rT}$

$\mathrm{W}=\left(\frac{4}{3}\right) \pi^2 \mathrm{rT}$

$\mathrm{W}=2 \pi \mathrm{r} \mathrm{T}$

MHT CET 2024 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

A ball rises to surface at a constant velocity in liquid whose density is 4 times greater than that of the material of the ball. The ratio of the force of friction acting on the rising ball and its weight is

$3: 1$

$4: 1$

$1: 3$

$1: 4$

MHT CET 2024 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

A drum of radius ' $R$ ' full of liquid of density ' $d$ ' is rotated at angular velocity ' $\omega$ ' $\mathrm{rad} / \mathrm{s}$. The increase in pressure at the centre of the drum will be

$\frac{\omega^2 R^2 d}{2}$

$\frac{\omega^2 \mathrm{Rd}}{2}$

$\frac{\omega \mathrm{Rd}^2}{2}$

$\frac{\omega^2 R^2 d^2}{2}$

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