MHT CET 2024 9th May Morning Shift | Heat and Thermodynamics Question 55 | Physics

A gas is contained in closed vessel. The initial temperature of the gas is $100^{\circ} \mathrm{C}$. If the pressure of the gas is increased by $4 \%$, the increase in the temperature of the gas is

$2^{\circ} \mathrm{C}$

$3^{\circ} \mathrm{C}$

$4^{\circ} \mathrm{C}$

$5^{\circ} \mathrm{C}$

MHT CET 2024 9th May Morning Shift

MCQ (Single Correct Answer)

-0

For an ideal gas, in an isobaric process, the ratio of heat supplied ' $Q$ ' to the work done ' $w$ ' by the system is ( $\gamma=$ ratio of specific heat at constant pressure to that at constant volume)

$\frac{1}{\gamma}$

$\frac{1}{\gamma-1}$

$\frac{\gamma}{\gamma-1}$

$\frac{\gamma-1}{\gamma}$

MHT CET 2024 9th May Morning Shift

MCQ (Single Correct Answer)

-0

The temperature of a gas is $-80^{\circ} \mathrm{C}$. To what temperature the gas should be heated so that the r.m.s. speed is increased by 2 times?

$499^{\circ} \mathrm{C}$

$772^{\circ} \mathrm{C}$

$1464^{\circ} \mathrm{C}$

$1737^{\circ} \mathrm{C}$

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

-0

Two bodies ' X ' and ' Y ' at temperatures ' $\mathrm{T}_1$ ' K and ' $T_2$ ' K respectively have the same dimensions. If their emissive powers are same, the relation between their temperatures is

$\frac{T_1}{T_2}=\frac{1}{3}$

$\frac{\mathrm{T}_1}{\mathrm{~T}_2}=\frac{81}{1}$

$\frac{\mathrm{T}_1}{\mathrm{~T}_2}=\frac{3^{\frac{1}{4}}}{1}$

$\frac{T_1}{T_2}=\frac{9^{\frac{1}{4}}}{1}$

PREVIOUS NEXT

MHT CET Subjects