1
MHT CET 2021 23rd September Evening Shift
+1
-0

A cylindrical rod has temperatures '$$T_1$$' and '$$T_2$$' at its ends. The rate of flow of heat is '$$Q_1$$' cal $$\mathrm{s}^{-1}$$. If length and radius of the rod are doubled keeping temperature constant, then the rate of flow of heat '$$\mathrm{Q}_2$$' will be

A
$$\mathrm{Q}_2=\frac{\mathrm{Q}_1}{2}$$
B
$$\mathrm{Q}_2=\frac{\mathrm{Q}_1}{4}$$
C
$$\mathrm{Q_2=4 Q_1}$$
D
$$\mathrm{Q}_2=2 \mathrm{Q}_1$$
2
MHT CET 2021 23rd September Evening Shift
+1
-0

The initial pressure and volume of a gas is '$$\mathrm{P}$$' and '$$\mathrm{V}$$' respectively. First by isothermal process gas is expanded to volume '$$9 \mathrm{~V}$$' and then by adiabatic process its volume is compressed to '$$\mathrm{V}$$' then its final pressure is (Ratio of specific heat at constant pressure to constant volume $$=\frac{3}{2}$$)

A
6 P
B
27 P
C
3 P
D
9 P
3
MHT CET 2021 23th September Morning Shift
+1
-0

If $$\mathrm{m}$$' represents the mass of each molecules of a gas and $$\mathrm{T}$$' its absolute temperature then the root mean square speed of the gas molecule is proportional to

A
$$\mathrm{m^{-\frac{1}{2}}T^{\frac{1}{2}}}$$
B
mT
C
$$\mathrm{m^{\frac{1}{2}}T^{-\frac{1}{2}}}$$
D
$$\mathrm{m^{\frac{1}{2}}T^{\frac{1}{2}}}$$
4
MHT CET 2021 23th September Morning Shift
+1
-0

An ideal gas at pressure '$$p$$' is adiabatically compressed so that its density becomes twice that of the initial. If $$\gamma=\frac{c_p}{c_v}=\frac{7}{5}$$, then final pressure of the gas is

A
p
B
2p
C
$$\frac{7}{5}$$p
D
2.63p
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